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Nat2105 [25]
4 years ago
14

A deposit of $4,500 at 5% for 3 years:

Mathematics
1 answer:
tekilochka [14]4 years ago
7 0
I = 4500 × 0.05 × 3
<span>I = $ 675.00</span>
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2. A soccer field is bordered on three sides by a parking lot of width x. The total
notsponge [240]

Answer: 50m

Step-by-step explanation:

this is the logical way I solved it:

1. Find the area of the entire area thing

300*200=60000

2. Subtract the area of the field from the area of the entire place

60000-30000=30000

3. Divide the area of the parking by three because there are three sides

30000 ÷ 3 = 10000

4. Divide 10000 by 200, not 300 because we want to find the side with one <em>x</em>, not two <em>x</em> (there are two sides adding on to the side with 300, but only one side on the side with 200)

10000÷200= 50

I know the steps are weird, but I know this is the right answer because this was on the unit test (same misspelling and everything lol) and during tutoring my teacher showed me how to do it, but of course I had to forget the steps.

4 0
3 years ago
ILL GIVE BRAINLIST IF U ANSWER THIS QUESTION
Yakvenalex [24]
57 degrees because 180-123= 57 degrees
7 0
3 years ago
Backgammon is a board game for two players in which the playing pieces are moved according to the roll of two dice. players win
Ivahew [28]

The rolls of the dice are independent, i.e. the outcome of the second die doesn't depend in any way on the outcome of the first die.

In cases like this, the probability of two events happening one after the other is the multiplication of the probabilities of the two events.

So, the probability of rolling two 6s is the multiplication of the probabilities of rolling a six with the first die, and another six with the second:

P(\text{rolling two 6s}) = P(\text{rolling a 6}) \cdot P(\text{rolling a 6}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

Similarly,

P(\text{rolling two 3s}) = P(\text{rolling a 3}) \cdot P(\text{rolling a 3}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

Actually, you can see that the probability of rolling any ordered couple is always 1/36, since the probability of rolling any number on both dice is 1/6:

P(\text{rolling any ordered couple}) = P(\text{rolling the first number}) \cdot P(\text{rolling the second number}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

7 0
3 years ago
A = a+b+c / 3
IgorLugansk [536]
The equation given in the question is 

<span>A = a+b+c / 3
3A = a + b + c
3A - a - c = b

From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your desired help.</span>
3 0
3 years ago
A bag contains 2 white marbles and 7 purple marbles. Two marbles are drawn at random. One marble is drawn and not replaced, then
skelet666 [1.2K]

A. likely

B. unlikely

C. There is a greater chance in picking to purple marbles because there are less of the white and more purple.

Hallie should spin the wheel because u have a greater chance of landing on a 5 then rolling two number cubes and hoping both number cubes come to equal 5.

4 0
3 years ago
Read 2 more answers
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