suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Answer:
109
Step-by-step explanation:
81-19 is 62. if you add 109 then you could do 109-19 is 90
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Answer:
$412.92
Step-by-step explanation:
You are going to want to use the compound interest formula, which is shown below.

<em>P = initial balance
</em>
<em>r = interest rate
</em>
<em>n = number of times compounded annually
</em>
<em>t = time
</em>
<em />
The first step is to change 4% into its decimal form:
4% ->
-> 0.04
Now plug in the values:


It would be worth $412.92