First we are going to find divided by 100 and multiply 20 is equal to four.
We are gonna use x to represent this number.
x/100 * 20 = 4
Solve for x
Therefore x = 20cm
Now that we found x the side of the larger square we are gonna find the area which is side^2.
20 * 20
Therefore the area of the larger square is 400cm^2
Answer: The flagpole is about 22.3 feet tall.
This is roughly the size of a two story building, assuming each floor is 10 feet or so.
Since this height is under 25 ft, this flagpole is in compliance with the regulation.
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Work Shown:
The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.
The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.
Use the tangent rule to connect the opposite and adjacent sides.
Solve for x.
tan(angle) = opposite/adjacent
tan(25) = (x-5.5)/36
36*tan(25) = x-5.5
x-5.5 = 36*tan(25)
x = 36*tan(25)+5.5
x = 22.28707569358
x = 22.3 ft is the approximate height of the flagpole
Make sure your calculator is in degree mode.
The height is not over 25 ft, so this flagpole meets the requirements.
Answer:
x= 16
Step-by-step explanation:
8x + 50 = 178
8x = 178- 50
8x = 128
x = 128/8
x = 16
11400 ÷12 = 950 hundreds
95000 x 100/25 = $380,000 <== value of the property
Answer:
Step-by-step explanation:
1. Replace F(x) with y.
2. Interchange x and y in y = 2x + 1: x = 2y + 1
3. Solve this result for y: 2y = x - 1, or y = (x - 1)/2
4. Replace y with:
-1
F (x):
-1 x - 1
F (x) = -----------
2
