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Ad libitum [116K]
3 years ago
8

Consider the following expression and determine which statements are true. x^2+5yz−8

Mathematics
1 answer:
statuscvo [17]3 years ago
8 0

Answer:

A.there are 3 terms.

B.the variables are x, y, and z.

Step-by-step explanation:

Complete question below:

Consider the following expression and determine which statements are true. x^2+5yz−8

CHOOSE 2 ANSWERS)

A.there are 3 terms.

B.the variables are x, y, and z.

C.The coefficient of x is 2.

D.the term 5yz is made up of 2 factors

The expression x^2+5yz-8

has three terms namely: x^2, 5yz and -8

The variables are x, y and z

The coefficient of x is 1 not 2, so option c is wrong

The term 5yz is made up of more than two factors namely 5, y, z, 5y, 5z, 5yz . So option d is also wrong.

The correct answers are option a and option b

A.there are 3 terms.

B.the variables are x, y, and z

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Answer:

Step-by-step explanation:

acceleration, a = 20 m/s^2

initial velocity, u = 0 since it starts from rest

final velocity, v = 400 m/s

v = u + at

400 = 0 + 20 t

400 = 20 t

t = 400 / 20

<u><em>t = 20 sec</em></u>

Hope this helps

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Compare the triangles and determine whether they can be proven congruent by SSS, SAS, ASA, AAS, or HL. If not, type "NONE".
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Step-by-step explanation:

6 0
3 years ago
An equation parallel and perpendicular to 4x+5y=19
UNO [17]

Answer:

Parallel line:

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

y=\frac{5}{4}x-\frac{1}{2}

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

4x+5y=19

we can change it into y=mx+b form

5y=-4x+19

y=-\frac{4}{5}x+\frac{19}{5}

so,

m=-\frac{4}{5}

Parallel line:

we know that slope of two parallel lines are always same

so,

m'=-\frac{4}{5}

Let's assume parallel line passes through (1,1)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-1=-\frac{4}{5}(x-1)

now, we can solve for y

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

m'=\frac{5}{4}

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-2=\frac{5}{4}(x-2)

now, we can solve for y

y=\frac{5}{4}x-\frac{1}{2}


4 0
3 years ago
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