According to Vieta's Formulas, if
are solutions of a given quadratic equation:
Then:
is the completely factored form of
.
If choose
, then:
So, according to Vieta's formula, we can get:
But
:
![d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2](https://tex.z-dn.net/?f=d%5E4-8d%5E2%2B16%3D%28d%5E2-4%29%5E2%3D%5B%28d%2B2%29%28d-2%29%5D%5E2%3D%28d%2B2%29%5E2%28d-2%29%5E2)
Answer:
im not sure of number 1 but number 2 is 60 120 180 and 240 hope this helps :D
Step-by-step explanation:
A shape is similar if corresponding angles are equal & if one is an enlargement of the other.
(I. E., one shape is twice as big as the other one.)
So, compare the lengths to find a common scale factor (of 2, for example, where you multiple by 2 to get a value & divide to get original value, from one shape to another.)
Hope this helps!
Answer:
Yes to all 3 questions.
Step-by-step explanation:
3x^2(x-1) + -3x^3+ 4x^2-2x+1
= 3x^3 - 3x^2 - 3x^3 + 4x^2 - 2x + 1
= x^2 - 2x + 1,
So A + B is a polynomial.
3x^2(x-1) - (-3x^3+ 4x^2-2x+1)
= 3x^3 - 3x^2 + 3x^3 - 4x^2 + 2x - 1
= 6x^3 - 7x^2 + 2x - 1.
So A - B is also a polynomial.
3x^2(x-1)( -3x^3+ 4x^2-2x+1)
= (3x^3 - 3x^2) ( -3x^3 + 4x^2 - 2x + 1)
= -9x^6 + 12x^5 - 6x^4 + 3x^3 + 9x^5 - 12x^4 + 6x^3 - 3x^2
= -9x^6 + 21x^5 - 18x^4 + 9x^3 - 3x^2.
So A * B is a polynomial.
Answer:
The answer is
Step-by-step explanation:
C. f(x) = 500(2)^x
2020
