How do I find the answer to 3km 6hm 7dam 5m ÷ 15?

Need help please explain w answer if you can.

uranmaximum [27]

Start by looking at the components of the line, basically the legs if you were to make it a right triangle.
components = < x1 - x2, y1 - y2 >
< 10-5 , 12-4 > = < 5 , 8 >
So the line starts at A and goes right 5 then up 8 to point B.

We need a point 3:1 distance which means that if X is our new point, length AX is 3 times length of XB.

3+1 = 4 parts total
Point X will be 3/4 distance

3/4 the components
< 5(3/4) , 8(3/4) > = < 15/4 , 6 >
Add these to point A to go right and up to the new point X.

(5 + 15/4 , 4 + 6) = (35/4 , 10)
35/4 = 8 3/4
so the first one is correct.

7 0

3 years ago

(5x+2y=23 (13x+3y=51

AysviL [449]

Answer:

$[3, 4]$

Step-by-step explanation:

{5x + 2y = 23

{13x + 3y = 51

−5⁄13[13x + 3y = 51]

{5x + 2y = 23

{−5x - 1 2⁄13y = 19 8⁄13 >> New Equation

______________________

11⁄13y = 3 5⁄13

_____ ______

11⁄13 11⁄13

$y = 4$ [Plug this back into both equations above to get the x-coordinate of 3]; $3 = x$

I am joyous to assist you anytime.

7 0

4 years ago

A triangle has two sides of lengths 8and 10 what value could the length of the third side be

Aleks04 [339]

Answer:

$\sqrt{164}$

Step-by-step explanation:

Pythagorean theorem

$8^{2} +10^2=164\\\sqrt{164}\\$

8 0

3 years ago

HELP!!!

ella [17]

Answer:

120

Step-by-step explanation:

We are given that the function for the number of students enrolled in a new course is $f(x) = 4^{x}-1$ .

It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.

We know that the average rate of change is given by,

$A = \frac{f(x)-f(a)}{x-a}$ ,

where f(x)-f(a) is the change in the function as the input value (x-a) changes.

Now, the number of students enrolled at 4 = f(4) = $f(x) = 4^{4}-1$ = 255 and the number of students enrolled at 2 = f(2) = $f(x) = 4^{2}-1$ = 15

So, the average increase $A=\frac{f(4)-f(2)}{4-2}$ = $A=\frac{255-15}{4-2}$ = $A=\frac{240}{2}$ = 120.

Hence, the average increase in the number of students enrolled is 120.

3 0

4 years ago

Look at the circle you created that has point C (the midpoint of AB) as its center and passes through point A. What can you say

Mice21 [21]

The inscribed angle on the circumference of the circle subtended by the diameter at the center is a right angle

What can be said about segment AB is; Segment AB is the diameter of circle with midpoint at C

What can be said about angle BDA is; Angle BDA is an inscribed angle of the circle with midpoint at C, subtended by the diameter AB at the center

The measure of angle BDA is 90°

What can be said about angle BEA is; Angle BEA is an inscribed angle of the circle with midpoint at C, subtended by the diameter AB at the center

The measure of angle BEA is 90°

The given diagram shows;

Circle with midpoint C, along AB, and radius AC

The diameter of circle C = AB

Circle with midpoint A, intersecting with circle C at points D and E

Tangents from point B on circle, C, intersect with circle A at points D and E

Required parameters;

What can be said about AB

The segment AB is a line that intersects the circle C at two points and also passes through the the point C which is the center of the circle C

Therefore, the segment AB is the diameter of the circle with center at C

What can be said about angle BDA

The angle BDA is the inscribed angle of circle C subtended by the points A and B which specifies the diameter of the circle with midpoint C

Therefore, the angle BDA is subtended by the diameter of the circle at the center

According to circle theorem, we have;

Angle subtended at the center = 2 × The angle subtended at the circumference

The angle subtended at the center by the diameter AB = 180° (Angle on a straight line)

Therefore;

The angle subtended at the center = 180° = 2 × Angle BDA

Angle BDA = 180°/2 = 90°

Angle BDA = 90°

What can be said about angle BEA

Similarly, we have;

The angle subtended at the center = 180° = 2 × Angle BEA

Angle BEA = 180°/2 = 90°

Angle BEA = 90°

Find out more about inscribed angles of a circle here:

brainly.com/question/17021375

7 0

3 years ago