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zhuklara [117]
3 years ago
6

Help me with math please

Mathematics
1 answer:
slava [35]3 years ago
3 0
Both of these lines share the relationship together of being parallel. 
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Y+5=-(x+5) in standard form
swat32

1. y+5=-x-5

2. y=-x-5-5

3.y=-x-10

4. y=x-10

_______________________

1. distribute negative sign

2. move the constant to the right and change the sign

3. -5-5 equals -10, bring everything down

4. change the sign of the x to positive, the equation is in standard form

5 0
3 years ago
Find the value of x to the nearest tenth!
sergij07 [2.7K]

Answer:

5.7

Step-by-step explanation:

sine cosine tangent

soh cah toa

sine = opposite/hypotenuse

so sin(35)= x/10

you can multiply 10 to both sides to get rid of the 10 denominator on the right leaving you with 10sin(35)=x

be sure your calculator is in degrees.

put that into a calculator leaving you with 5.7

5 0
3 years ago
Help pls Use the substitution method to solve the system of equations. Choose the
AURORKA [14]
If I’m using substitution the answer is A
6 0
3 years ago
In Jaden’s yard, there is a triangular garden patch. He wants to plant a geranium in the patch at a point equidistant from all i
Lelu [443]

Answer:

Jaden has to plant the geranium in the circumcentre of the triangular yard in order such that it is equidistant from all its vertices.

Step-by-step explanation:

In Jaden’s yard, there is a triangular garden patch. He wants to plant a geranium in the patch at a point equidistant from all its vertices.

<em>" The CIRCUMCENTER (C) of a triangle is the point in the plane equidistant from the three vertices of the triangle "</em>

Hence Jaden has to plant the geranium in the circumcentre of the triangular yard in order such that it is equidistant from all its vertices.



5 0
3 years ago
Read 2 more answers
What is the sum of the first 4 terms of a geometric sequence that has a first term of 2 and a ratio (multiplier) of 8?
taurus [48]

\bf \qquad \qquad \textit{sum of a finite geometric sequence} \\\\ S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad  \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ a_1=2\\ r=8\\ n=4 \end{cases} \\\\\\ S_4=2\left( \cfrac{1-8^4}{1-8} \right)\implies S_4=2\left( \cfrac{-4095}{-7} \right) \\\\\\ S_4=2(585)\implies S_4=1170

6 0
3 years ago
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