Question

The international cricket team is going to stadium to play the T20 cricket game. A coordinate grid is superimposed on a highway map of the city. The team hotel is at point (3, 4) and the stadium is at point (7, 1). The map shows a rest stop halfway between the hotel and the stadium. What are the coordinates of the rest stop? What is the approximate distance between the hotel and the stadium? (One unit is approximately equal to 6.4 miles.)

Answer 1

Answer:

The coordinate of the rest stop is: $(5,2.5)$

The distance between the hotel and the stadium is 32 miles

Step-by-step explanation:

Given

$(x_1,y_1) = (3,4)$ --- Team hotel

$(x_2,y_2) = (7,1)$ --- Stadium

Solving (a): The coordinates of the rest stop

The rest stop is at half way;

So, the coordinate is:

$(x,y) = \frac{1}{2}(x_1+x_2,y_1+y_2)$

This gives:

$(x,y) = \frac{1}{2}(3+7,4+1)$

$(x,y) = \frac{1}{2}(10,5)$

Open bracket

$(x,y) = (5,2.5)$

Solving (b): Distance between the hotel and the stadium

We have:

$(x_1,y_1) = (3,4)$ --- Team hotel

$(x_2,y_2) = (7,1)$ --- Stadium

The distance (d) is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

So, we have:

$d = \sqrt{(3 - 7)^2 + (4 - 1)^2}$

$d = \sqrt{(-4)^2 + 3^2}$

$d = \sqrt{16 + 9}$

$d = \sqrt{25}$

$d =5$

From the question, we have:

$1\ unit = 6.4\ miles$

So:

$d =5 * 6.4\ miles$

$d =32\ miles$