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vladimir1956 [14]
3 years ago
10

Is this right? If not someone explain to me why it’s not. :)

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

x= 14√3

y= 28√3

Step-by-step explanation:

Please see attached picture for full solution.

(tan30° and cos30° are special angles so there's an exact value to it in which we can memorise.)

In this case, by Pythagoras's Theorem, you should ensure that:

{y}^{2}  = 42^{2}  +  {x}^{2}

✓ Let's check:

{y}^{2}  = (28 \sqrt{3} )^{2}  \\ y^{2}  = 2352 \\  {x}^{2} +  {42}^{2}  = ( 14\sqrt{3})^{2} + 1764  = 2352

This satisfies Pythagoras' Theorem :)

For this kind of questions, first label the adjacent side, opposite side and the hypotenuse side of the triangle.

Cosine angle= adjacent/ hypotenuse

Sine angle= opposite/ hypotenuse

tangent angle= opposite/ adjacent

Then substitute the known side and angle to find the unknown side.

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Write the direct variation function given that y varies directly with x, and y = 16 when x = 4.
Otrada [13]

Answer:

Very little information is given, leaving room to multiple possible functions, however i would expect it to be y = 4x

Step-by-step explanation:

x * z = y

4 * z = 16

z = 16/4

z = 4

5 0
3 years ago
Please help!! x = 2 - 3 cos t, y = 1 + 4 sin t in rectangular form?<br><br> thank you! :)
sukhopar [10]

Answer:

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

Step-by-step explanation:

x=2-3\cos(t)

y=1+4\sin(t)

Let's solve for \cos(t) in the first equation and then solve for \sin(t) in the second equation.

I will then use the following identity to get right of the parameter, t:

\cos^2(t)+\sin^2(t)=1 (Pythagorean Identity).

Let's begin with x=2-3\cos(t).

Subtract 2 on both sides:

x-2=-3\cos(t)

Divide both sides by -3:

\frac{x-2}{-3}=\cos(t)

Now time for the second equation, y=1+4\sin(t).

Subtract 1 on both sides:

y-1=4\sin(t)

Divide both sides by 4:

\frac{y-1}{4}=\sin(t)

Now let's plug it into our Pythagorean Identity:

\cos^2(t)+\sin^2(t)=1

\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1

\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

5 0
3 years ago
Read 2 more answers
Determine the value of w and x in the figure below. (Thanks for the help I really appreciate it!)​
storchak [24]
Triangle HAM looks like an isosceles triangle, and we know that in an isosceles triangle 2 of the angles are the same.

so :
180 - 106 = 74 ( sum of the other 2 angles )
74/2 = 37 ( sum of angle HMA / HAM )

angles on a straight line add up to 180.
180-37=143 ( angle x )

since triangle YMH is also an isosceles,
180-37=143
143/2=71.5 ( angle w )
7 0
4 years ago
Simplify.√75 <br> A.3√5 B.15√5 C.25√3 D. 5√3
stich3 [128]
D, square root of 75= 5 square root 3
6 0
3 years ago
Solve the Equation |x-8|=16
choli [55]
|x-8| = 16
⇒ x-8= 16 or x-8= -16
⇒ x= 16+ 8 or x= -16+ 8
⇒ x= 24 or x= -8

Final answer: x= 24 or x= -8~
4 0
3 years ago
Read 2 more answers
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