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spin [16.1K]
2 years ago
13

For the following conditional, identify the converse and the truth value of the converse:

Mathematics
2 answers:
Yanka [14]2 years ago
8 0

Answer: The answer is (B)  If an angle has measure 90°, then it is a right angle.  True.

Step-by-step explanation:  The given conditional statement is

" If an angle is a right angle, then its measure is 90°."

We are to write the converse of the above conditional statement.

We know that if the statement is "If p, then q", then its converse will be "If q, then p".

So, the converse of our given statement will be

"If an angle has measure 90°, then it is a right angle."

Since this statement is always true, so the correct option is (B).

melamori03 [73]2 years ago
4 0
The answer to the question is B  
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The volume of a cylinder is 12,566.4 cm3. The height of the cylinder is 8 cm.
scoundrel [369]
Using the formulas here: http://www.1728.org/diamform.htm

A)  Volume   =   <span>π <span>• r² • height
radius^2 = Volume / (PI*height)
</span></span><span>radius^2 = 12,566.4 / (PI * 8)
</span>radius^2 =  <span> <span> <span> 500.0011692175 </span> </span> </span>
radius = <span> <span> <span> 22.3607059195 </span> </span> </span>
radius (rounded) = 22.4 cm

B) Area of base = PI * radius^2
Area of base = 3.14159265 * 500
Area of base = <span> <span> <span> 1,570.7963267949 </span>
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C) <span><span>lateral area = </span>2 • </span><span>π • r • height </span>
<span>lateral area = 2 • </span><span>π • 22.4 * 8
</span>lateral area = <span> <span> <span> 1,125.9468070466 </span> </span> </span>
lateral area = 1,125.9 <span>square cm

D) Total Surface Area = </span><span>(2 • <span>π <span>• r²) + (2 • <span>π • r • height)</span></span></span></span>
Total Surface Area = <span><span>2 * (top AND bottom area which is the Part B answer times 2) + (the lateral area which is the Part C answer)
</span>
Total Surface Area = </span>( 2 * 1,570.8 ) + (1,125.9)
<span>Total Surface Area = 3,141.6 + 1,125.9
</span><span>Total Surface Area = </span> <span> <span> <span> 4,267.5 </span> </span> </span> square cm





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3 years ago
A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).
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~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}

\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}

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