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2 years ago

Can somebody help me? anybody know the answer

Mathematics

1 answer:

tigry1 [53]2 years ago

7 0

Answer:

25 = c

Step-by-step explanation:

You had a good start on filling in the values in the Pythagorean Theorem. The work needed to be finished.

$a^2 +b^2 = c^2\\\\20^2 +15^2=c^2\\\\400+225=c^2\\\\625=c^2\\\\\sqrt{625}=\sqrt{c^2}\\\\\boxed{25=c}$

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Emily needs enough Fabric for 3 1/2 hats. Since she has half a hat done. If each bag requires 1 2/7 ft of Fabric, how much fabri

kow [346]

first off let's convert the mixed fractions to improper fractions.

$\stackrel{mixed}{3\frac{1}{2}}\implies \cfrac{3\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{7}{2}} ~\hfill \stackrel{mixed}{1\frac{2}{7}}\implies \cfrac{1\cdot 7+2}{7}\implies \stackrel{improper}{\cfrac{9}{7}}$

she already did half a hat, so we can say $\cfrac{7}{2}-\cfrac{1}{2}\implies \cfrac{7-1}{2}\implies 3$

so she only needs enough fabric to make 3 more full hats, we know each one uses 9/7 ft, so

$3\cdot \cfrac{9}{7}\implies \cfrac{27}{7}\implies 3\frac{6}{7}$

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2 years ago

Help with 11, 12, 13 pls. You get 10 points

Eddi Din [679]

11. m=5 p=15
12. g=3 k=3
13. b=40

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3 years ago

Identify the property shown. −1.4+(−2.6+3.8)=(−1.4+(−2.6))+3.8

Dimas [21]

<span>This property is called associativity. It shows that it doesn't matter whether you perform the sum on the first two numbers and then the third, or on the second two and then the first, because you will get the same answer either way. That is because addition is associative.</span>

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4 years ago

Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets for a flight that holds only 12

melamori03 [73]

Answer:

98.75% probability that every passenger who shows up can take the flight

Step-by-step explanation:

For each passenger who show up, there are only two possible outcomes. Either they can take the flight, or they do not. The probability of a passenger taking the flight is independent from other passenger. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .