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Elena L [17]
3 years ago
10

Which decimal makes the number sentence true?

Mathematics
1 answer:
rjkz [21]3 years ago
5 0

Answer:

b.0.26 is the correct answer

Step-by-step explanation:

a is incorrect because that would be .40 and .40 is more than .27 so that would make the equation false

c is in correct because .3 is.30 and .30 is more than. 27 and this would make the equation false

and d is incorrect because .28 is more than. 27 would make the equation false

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Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB
Digiron [165]

Answer: The distace between midpoints of AP and QB is \frac{a}{8}.

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = \frac{AP}{2}

QB = \frac{AP}{2}

Substituing:

AP + 2*(\frac{AP}{2}) = a

2AP = a

AP = \frac{a}{2}

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = \frac{AP}{2}

QB = \frac{a}{2}*\frac{1}{2}

QB = \frac{a}{4}

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}

\frac{AP}{2} = \frac{a}{4}

<u>Midpoint of QB</u>:

\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}

\frac{QB}{2} = \frac{a}{8}

The distance is:

d = \frac{a}{4} - \frac{a}{8}

d = \frac{a}{8}

4 0
3 years ago
Pleas help me and answer ASAP
Grace [21]
Area = 5 units × 3 units
Area = 15 square units
5 0
3 years ago
Read 2 more answers
Which conversions from scientific notation to standard notation are true? Select the four correct answers
bogdanovich [222]

The options are missing, so i have attached them.

Answer:

options B, E, G & H are correct.

Step-by-step explanation:

A) We are given;

1.71 × 10³ = 0.00171

For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point to the right of 1.71 three times because the exponent is 3.

Thus, the proper conversion is;

1.71 × 10³ = 1710

B) We are given;

8.05 × 10^(5) = 805000

For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point five times to the right of 8.05 because the exponent is 5.

Thus, the proper conversion is;

8.05 × 10^(5) = 805000

C) We are given;

2.4 × 10⁴ = -24000

For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point four times to the right of 2.4 because the exponent is 4.

Thus, the proper conversion is;

2.4 × 10⁴ = 24000

D) We are given;

8.25 × 10^(-3) = -8250

For this conversion, the exponent attached to 10 is negative. This means we will have to move the decimal point three times to the left of 8.25 because the exponent is -3.

Thus, the proper conversion is;

8.25 × 10^(-3) = 0.00825

E) We are given;

7.09 × 10^(-6) = 0.00000709

For this conversion, the exponent attached to 10 is negative. This means we will have to move the decimal point six times to the left of 7.09 because the exponent is -6.

Thus, the proper conversion is;

7.09 × 10^(-6) = 0.00000709

F) We are given;

3.99 × 10^(5) = 300,099

For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point five times to the right of 3.99 because the exponent is 5.

Thus, the proper conversion is;

3.99 × 10^(5) = 399,000

G)We are given;

8 × 10^(7) = 80,000,000

For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point seven times to the right of 8 because the exponent is 7.

Thus, the proper conversion is;

8 × 10^(7) = 80,000,000

H) We are given;

1.03 × 10^(-4) = 0.000103

For this conversion, the exponent attached to 10 is negative. This means we will have to move the decimal point four times to the left of 1.03 because the exponent is -4.

Thus, the proper conversion is;

1.03 × 10^(-4) = 0.000103

Looking at all the options as well as the proof I got, only options B, E, G & H are correct.

7 0
3 years ago
What is the sum of 667 and 23?<br> a. 644<br> b. 690<br> c. 15,341<br> d. 29
Delicious77 [7]
The answer is B. 690
5 0
3 years ago
Read 2 more answers
In ΔPQR, r = 9 inches, p = 6.6 inches and ∠Q=6°. Find the area of ΔPQR, to the nearest 10th of a square inch
Andreyy89

Answer:

2.8 square inches

Step-by-step explanation:

Area of the triangle PQR = 1/2 rp sin <Q

Given

r = 9in

p = 6.6in

<Q =6°

Substitute into the formula;

Area of the triangle PQR = 1/2 * 9 * 6 sin6°

Area of the triangle PQR = 9 * 3 sin6°

Area of the triangle PQR  = 27 sin6°

Area of the triangle PQR = 27(0.1045)

Area of the triangle PQR = 2.82

Hence the area to the nearest 10th of a square inch is 2.8 square inches

6 0
3 years ago
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