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umka2103 [35]
3 years ago
12

What is the solution for I

Mathematics
1 answer:
xeze [42]3 years ago
5 0

Answer:

no solution

Step-by-step explanation:

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Solve the exponential equation: 73 – 2x = 7–x
tigry1 [53]
I don't think any of them are the answer.
4 0
3 years ago
The question is in the picture i uploaded!!
torisob [31]

Answer:

Step-by-step explanation:

a) there are 6 red out of 18 total. 6/18 = 1/3

b) there are 14 that are not blue out of 18. 14/18 = 7/9

6 0
2 years ago
Read 2 more answers
What is the standard form equation of the line shown below? Graph of a line going through negative 1, 5 and 2, 4
natima [27]

Answer:

y = -1/3x + 14/3

Step-by-step explanation:

We have the standard equation as;

y = mx + b

where m is the slope and b is the y-intercept

the given points are;

(-1,5) and (2,4)

So we plug x and y for each of the points

then we create two linear equations which we can solve simultaneously to get the values of m and b

From the points;

5 = -m + b•••••••(i)

4 = 2m + b

from i;

b = 5 + m

substitute this into equation ii

4 = 2m + 5 + m

4 = 3m + 5

4-5 = 3m

3m = -1

m = -1/3

Recall;

b = 5 + m

b = 5-1/3

b = 14/3

so we have the equation as;

y = -1/3x + 14/3

Multiply through by 3

3y = -x + 14

7 0
3 years ago
X+3y = 2
nalin [4]

Answer:

The value of "x" is 5.

Step-by-step explanation:

In order to solve this system of equations, we first have to take the first equation and use it to represent "y" in terms of "x". We do that in the following way...

x + 3y = 2\\3y = 2 - x\\y = \frac{2}{3} - \frac{x}{3}

Now, we need to take the second equation and substitute "y" for the equivalent value in terms of "x". After doing this we will get the following equation, which we can solve to get the value of "x".

4x - 3y = 23\\4x-3(\frac{2}{3} - \frac{x}{3}) = 23\\4x - 2 + x = 23\\5x - 2= 23\\5x = 25\\x = 5

Therefore, the value of "x" is 5.

8 0
3 years ago
Please help me need to revise for a testtt!!!!
LUCKY_DIMON [66]
Remember you can add like terms exg, 3y+4y=7y 3y^2+4y^2=7y^2, but cannot add 3y^2 and 4y, or 3 and 4y so

3a+2w-5a-9w
group like trems
3a-5a+2w-9w
subtract
-2a-7w


3y^2+2w^2-y^2-w^2
group like terms (think of w^2 and y^2 as 1w^2 and 1y^2)
3y^2-y^2+2w^2-w^2
subtract
2y^2+w^2

2x+2x=4x
3 0
3 years ago
Read 2 more answers
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