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Ber [7]
3 years ago
10

What is (3 − 5i) − (-2 − 5i)?

Mathematics
1 answer:
vladimir1956 [14]3 years ago
8 0
your answer is 5 bc you want to rearrange the numbers like this                       (5i - 5i) - (3 -(-2))  so (5i - 5i)= 0 and 3 - (-2) is 5
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if you are looking to determine the range of the following set of numbers which number would you take as the smallest number 2,6
morpeh [17]
-5 is the smallest. I will put them in order for you (smallest to greatest) -5, -1, 2, 3, 6, 14, 18
3 0
3 years ago
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Which is the range of this function?<br> {(-5, 7), (-3, 10), (0, 2), (4, 6), (9, 0)}
qaws [65]

Answer:

{y | y = -9, -3, 0, 5, 7}

Step-by-step explanation:

i think thats the anwer

7 0
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What sum of money amounts Rs.3250 in 6 yrs at the rate of 5%?
kvasek [131]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Find the multiplier:

5% ==> 1.05

Use the formula:

final = original x multiplier^n

n is the number of years

Substitute in the values:

final = 3250 x 1.05^6

solve:

final = 4355.310832

The answer is Rs. 4355.31

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4 0
3 years ago
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Simplify the expression. 9r 3r2 – 5r 7
Ksenya-84 [330]
Your final answer is going to be 4r + 3r ^2 +7
7 0
3 years ago
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Please show your work this question what made you come to the conclusion. Thank you
AveGali [126]

Answer:

B the range, the x- and y-intercept

Step-by-step explanation:

the domain stays the same : all values of x are possible out of the interval (-infinity, +infinity).

but the range changes, as for the original function y could only have positive values - even for negative x.

the new function has a first term (with b) that can get very small for negative x, and then a subtraction of 2 makes the result negative.

the y-intercept (x=0) of the original function is simply y=1, as b⁰=1.

the y-intercept of the new function is definitely different, because the first term 3×(b¹) is larger than 3, because b is larger than 1. and a subtraction of 2 leads to a result larger than 1, which is different to 1.

the original function has no x-intercept (y=0), as this would happen only for x = -infinity. and that is not a valid value.

the new function has an x-intercept, because the y-values (range) go from negative to positive numbers. any continuous function like this must therefore have an x-intercept (again, y = the function result = 0)

3 {b}^{x + 1}  = 2

{b}^{x + 1}  = 2 \div 3

log_{b}(2 \div 3)  = x + 1

x =  log_{b}(2 \div 3)  - 1

8 0
3 years ago
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