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3 years ago

What is (3 − 5i) − (-2 − 5i)?

1 answer:

vladimir1956 [14]3 years ago

8 0

your answer is 5 bc you want to rearrange the numbers like this (5i - 5i) - (3 -(-2)) so (5i - 5i)= 0 and 3 - (-2) is 5

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1/5 x 6/7 ? A. 6/12 B.7/30 C.6/35 D.7/35

OverLord2011 [107]

In order to get the answer to this question you must multiply the numerators then multiply the denominators and reduce if needed.

$\frac{1}{5} \times\frac{6}{7}$

$1\times6=6$

$5\times7=35$

$=\frac{6}{35}$

Therefore your answer is option C "6/35."

Hope this helps.

5 0

4 years ago

I really need this can someone help solve asap!!!

Kryger [21]

Answer: to find this answer .we need to do pegothogs property

Step-by-step explanation:

30° + 90° = 90 (because it is right angle )

120° - 90° = 30°

Plz mark me as brainlist

thank you :-)

4 0

4 years ago

Can someone please help I will do anything

Aleks [24]

Answer:

678.24 cubic centimeters

Step-by-step explanation:

7 0

3 years ago

65% of what number is 78? A. 120 B. 143 C. 785 D. 5,070

RideAnS [48]

Answer:

Step-by-step explanation:

65% × 78 =

(65 ÷ 100) × 78 =

(65 × 78) ÷ 100 =

5,070 ÷ 100 =

50.7;

6 0

4 years ago

Read 2 more answers

Students who party before an exam are twice as likely to fail as those who don't party (and presumably study). If 20% of the stu

True [87]

Answer:

The fraction of the students who failed to went partying = $\frac{1}{10}$

Step-by-step explanation:

Let total number of students = 100

No. of students partied are twice the no. of students who not partied.

⇒ No. of students partied = 2 × the no. of students who are not partied

No. of students partied before the exam = 20 % of total students

⇒ No. of students partied before the exam = $\frac{20}{100}$ × 100

⇒ No. of students partied before the exam = 20

No. of students who not partied before the exam = $\frac{20}{2} = 10$

Thus the fraction of the students who failed to went partying = $\frac{10}{100} = \frac{1}{10}$

8 0

3 years ago