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MA_775_DIABLO [31]

3 years ago

15

Which of the following equations, where ddd is distance in miles and ttt is time in hours, represents a speed that is less than

that of the leatherback sea turtle?
Choose all answers that apply:

2 answers:

Alexandra [31]3 years ago

7 0

Answer:

c

Step-by-step explanation:

this helps

ratelena [41]3 years ago

4 0

Answer: The answer is A and B

Step-by-step explanation:

You might be interested in

What is the answer to this solution. -7r−4≥ 4r+2

tia_tia [17]

Answer:

The solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

Step-by-step explanation:

Given the expression

$-7r-4\ge \:4r+2$

Add 4 to both sides

$-7r-4+4\ge \:4r+2+4$

Simplify

$-7r\ge \:4r+6$

Subtract 4r from both sides

$-7r-4r\ge \:4r+6-4r$

Simplify

$-11r\ge \:6$

Multiply both sides by -1 (reverses the inequality)

$\left(-11r\right)\left(-1\right)\le \:6\left(-1\right)$

Simplify

$11r\le \:-6$

Divide both sides by 11

$\frac{11r}{11}\le \frac{-6}{11}$

Simplify

$r\le \:-\frac{6}{11}$

Therefore, the solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

7 0

3 years ago

F(x)=x+3 , G(x)=x^2-2<br> (F/G)(-1)-G(3)

trapecia [35]

$f(x)=x+3;\ g(x)=x^2-2\\\\\left(\dfrac{f}{g}\right)(-1)-g(3)=?\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\g(3)=3^2-2=9-2=7\\\\f(-1)=-1+3=2\\\\g(-1)=(-1)^2-2=1-2=-1\\\\\left(\dfrac{f}{g}\right)(-1)-g(3)=\dfrac{2}{-1}-7=-2-7=-9$

7 0

3 years ago

9+4+3+5+1+0+1+0+0 divided by 8

Lana71 [14]

Answer:

3.875

Step-by-step explanation:

Add all of them then divide.

5 0

3 years ago

Read 2 more answers

Which of the following statements is biconditional?

bazaltina [42]

Answer with Step-by-step explanation:

We are given some statements

We have to find that which statements is bi-conditional

We know that

Bi-Conditional statement:It is combination of conditional statement and its converse written as if and only if .Bi- conditional statement is true if and only both the conditions are true.

1.I am sleeping if and only if I am snoring.

If I am sleeping then I am snoring .Then,it may be true or may not be true.

If I am snoring then I am sleeping .It is true.

Its one side true result.So, it is not bi conditional true statement.

2.Mary will eat pudding today if and only if is custard.

If Mary will eat pudding today then it is custard.It may or may not be true because pudding can be any soft sweet desserts.It is not necessary that it is custard only.

If it is custard then Mary will east pudding today.It is true, because it is soft sweet dessert.

Hence, it is one side true. Therefore, It is not bi- conditional true.

3.It is raining if and only if it is cloudy.

If it is raining then it is cloudy .It is true.

But if it is cloudy then it is raining. It may be true or may not be true.

Hence, it is one side true result.Therefore, it is not bi conditional true.

Therefore, any given statement is not both side true.

So, the answer is none of the above because bi conditional statement is true if and only if both the conditions are true.

7 0

3 years ago

Given line AB and point O on that line, any ray that can be drawn with its endpoint at O can be put into a one- to-one correspon

natima [27]

Answer:

Protractor

Step-by-step explanation:

A POSTULATE, LAW OR THEORY SHOULD NEVER BE ALTERED

∴ The protractor postulate states that the measurement of an angle between two rays can be designated as a unique number, and this number would be between 0 and 180 degrees, Hence for every angle A, there corresponds a positive real number less than or equal to 180. This postulate guarantee the use of a protractor to measure angles.

Hence, Given line AB and point O on that line in such a way that any ray that can be drawn with its endpoint at O can be put into a one- to-one correspondence with the real numbers between 0 and 180 is a statement that explains Protractor's Postulate.

4 0

3 years ago