They are 90 apart on a number line
(2/5)(x-1)<(3/5)(x+1) perform indicated multiplications
(2x-2)/5<(3x+3)/5 multiply both sides by 5
2x-2<3x+3 add 2 to both sides
2x<3x+5 subtract 3x from both sides
-x<5 divide both sides by -1 (remember to reverse direction of inequality sign when multiplying/dividing by a negative value)
x>-5
Answer:
4y^2-y+21
Step-by-step explanation:
(4y-5y)+(5y^2-y^2)+(-6+27)
-y+4y^2+21
put it in standard form
4y^2-y+21
Answer: 
Step-by-step explanation:
We need;
We don't have the radius, but we do have the diameter. A diameter is twice the radius. Therefore, we can divide the diameter by 2 in order to obtain the radius.
Now plug this info into the formula.
![(3.14)(12yd)[(12yd)+\sqrt{(18yd)^2+(12yd)^2} ]](https://tex.z-dn.net/?f=%283.14%29%2812yd%29%5B%2812yd%29%2B%5Csqrt%7B%2818yd%29%5E2%2B%2812yd%29%5E2%7D%20%5D)
Let's solve the square root first.
![(3.14)(12yd)[(12yd)+\sqrt{324yd^2+144yd^2} ]](https://tex.z-dn.net/?f=%283.14%29%2812yd%29%5B%2812yd%29%2B%5Csqrt%7B324yd%5E2%2B144yd%5E2%7D%20%5D)
![(3.14)(12yd)[(12yd)+\sqrt{468yd^2} ]](https://tex.z-dn.net/?f=%283.14%29%2812yd%29%5B%2812yd%29%2B%5Csqrt%7B468yd%5E2%7D%20%5D)
![(3.14)(12yd)[(12yd)+\sqrt{468yd^2} ]\\(3.14)(12yd)(12yd+21.63yd)](https://tex.z-dn.net/?f=%283.14%29%2812yd%29%5B%2812yd%29%2B%5Csqrt%7B468yd%5E2%7D%20%5D%5C%5C%283.14%29%2812yd%29%2812yd%2B21.63yd%29)
Now solve the sum
Multiply
Answer:
wat
Step-by-step explanation:
