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3 years ago

What is the solution

Mathematics

1 answer:

ivolga24 [154]3 years ago

7 0

Answer:

Step-by-step explanation:

$\sqrt{2x+4} -\sqrt{x} =2\\\sqrt{2x+4} =2+\sqrt{x} \\squaring\\2x+4=4+x+4\sqrt{x} \\2x+4-4-x=4\sqrt{x} \\x=4\sqrt{x} \\again~squaring\\x^2=16x\\x^2-16x=0\\x(x-16)=0\\x=0,16$

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Nikolay [14]

Hey Aarya!

If we `scale` both the numerator and denominator by the same value, then we can create other equivalent fractions. By scale I mean: Multiply both the top and bottom of the fraction by the same value.

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4 years ago

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3 years ago

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