The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
ANSWER
EXPLANATION
A basic sine curve has equation in the form:
Where 'a' is the amplitude.
In this case a=2 because the amplitude is 2.
For a transformed sine function, the general equation is:
where a=2 is still the amplitude
This is also a sine function with an amplitude of 2.
Others include:
e.t.c
Is it multiple choice?
EDIT: The answer is 95.
Step-by-step explanation:
1. Use exterior angles (each adds up to 360) to find interior angles
2. Add this together
3.Take it away from 360
