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charle [14.2K]
3 years ago
9

Pythagorean theorem calc: find c, a=12.96148, b=11

Mathematics
1 answer:
eduard3 years ago
3 0
A = 12.96148 b = 11
a^2 + b^2 = c^2
(12.96148)^2 + (11)^2 = c^2
168 + 121 = c^2
289 = c^2
c = sqrt(289)
c = 17 I did a little bit of rounding to get this, but I'm sure it is close enough.
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What the biggest 7/2 or 3 1/4?​
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7/2 is bigger; there are three wholes in this fraction , with a 1/2 left over, which makes it 3 1/2.
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26. Matthew factored a 5th-order polynomial. Four of the factors are: (x-2), (x+2i), (x-4), and (x+4) .
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You may think there is no way to resolve this. Either of the first two look like they might work and you cannot be sure what you will get with the last two unless you know.

The answer is one of the last two. The equation cannot have just one or even a large number of complex numbers. When you are factoring a polynomial, the number of complex numbers must be even.

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I'll edit to add the graph.


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4 years ago
What is 637 rounded to the nearest 100
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If ∆ABC is an isosceles triangle and ∆DBE is an equilateral triangle, find each missing measure.​
sleet_krkn [62]

Answer:

∠1=∠9=43°,  ∠2=∠7= 17°,  ∠4=∠5=∠6=60°, ∠3=∠8=120°

Step-by-step explanation:

Given ABC is an isosceles triangle and DBE is an equilateral triangle. we have to find each missing measure.

In triangle ABC,

∠1=∠9    (∵isosceles triangle)

⇒ 4x+3=9x-47

⇒ 9x-4x=3+47 ⇒ 5x=50 ⇒ x=10

Hence, ∠9=∠1=(4x+3)°=4(10)+3=43°

Also, given ΔBDE is an equilateral triangle, and all angle of equilateral triangle are equal.

∴ ∠4+∠5+∠6=180°

⇒ ∠4+∠4+∠4=180° ⇒ 3∠4 = 180° ⇒ ∠4 = 60°

∴ ∠4=∠5=∠6=60°

By exterior angle property, ∠3=∠5+∠6=60°+60°=120°

                                            ∠8=∠5+∠4=60°+60°=120°

In ΔABD, ∠1+∠2+∠3=180°

            ⇒ 43°+120°+∠2=180°⇒ ∠2 = 17°

In ΔABD, ∠9+∠8+∠7=180°

            ⇒ 43°+120°+∠7=180°⇒ ∠7= 17°

Step-by-step explanation:

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