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miss Akunina [59]
3 years ago
7

Find the difference 213-98 or 6320-1289?

Mathematics
2 answers:
nlexa [21]3 years ago
7 0
1. 115 for the first question,
kari74 [83]3 years ago
6 0
115 is the answer for the first problem.5031 is the answer for the second question.
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Jordan’s class has 30 boys. If the students in his class, 60% are girls. How many girls are in Jonathan’s class?
aev [14]

There are 45 girls in Jonathan's class.

4 0
4 years ago
You go to the mall to make some purchases. You buy 3 dresses which cost $59.99 each and a pair of shoes that cost $75. What is t
mina [271]
Combine costs
59.99(3) + 75 = 179.97 + 75
179.97 + 75 = $254.99 (total cost)
Now add tax: 8% = 0.08
254.99 * 0.08 = 20.3992
254.99 + 20.3992 = 275.3892

Solution: bill would be around $275
6 0
3 years ago
The area of a rectangle is 42 milimeter .The length is 7 milimeters. What is the perimter of rectangel?
Leni [432]

Answer:

6 millimeters

Step-by-step explanation:

A = L × W

A ÷ L = W

42 ÷ 7 = 6

8 0
3 years ago
Read 2 more answers
Does 1/8 ÷ 5 equal 1/4 true or false?​
Llana [10]
True I think cause it’s divided by 5
6 0
3 years ago
Here are summary statistics for randomly selected weights of newborn​ girls: nequals202​, x overbarequals28.3 ​hg, sequals6.1 hg
Lorico [155]

Answer:

The confidence interval is 27.5 hg less than mu less than 29.1 hg

(A) Yes, because the confidence interval limits are not similar.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = 28.3 hg

sd = 6.1 hg

n = 202

degree of freedom = n-1 = 202-1 = 201

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value corresponding to 201 degrees of freedom and 5% significance level is 1.97196

E = t×sd/√n = 1.97196×6.1/√202 = 0.8 hg

Lower limit = mean - E = 28.3 0.8 = 27.5 hg

Upper limit = mean + E = 28.3 + 0.8 = 29.1 hg

95% confidence interval is (27.5, 29.1)

When mean is 28.3, sd = 6.1 and n = 202, the confidence limits are 27.5 and 29.1 which is different from 27.8 and 29.6 which are the confidence limits when mean is 28.7, sd = 1.8 and n = 17

7 0
4 years ago
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