Find the area of a rectangle with length (3x+2) units with width ( 4x+10 ) units
2 answers:
Area of rectangle = Length × Width
Length - (3x+2) Width - (4x+10)
Area of rectangle = (3x+2) × (4x+10)
Area of rectangle = 3x(4x+10) + 2(4x+10)
Area of rectangle = 12x² + 30x + 8x + 20
Area of rectangle = 12x² + 38x + 20
Hence , the area of rectangle is 12x² + 38x + 20 units
Answer:
Step-by-step explanation:
Area of rectangle = length * width
= (3x + 2)(4x + 10)
= 3x *(4x + 10) + 2*(4x + 10)
= 3x *4x + 3x *10 + 2*4x + 2*10
= 12x² + <u>30x + 8x</u> + 20 {Combine like terms}
= 12x² + 38x + 20
You might be interested in
Answer:
5) EG=HG because it's corresponding part of congruent triangles are congruent (CPCTC )
Answer:
The selection was made by a 10-strong jury instead of the former public vote, which ... a capacity of 12 musicians ;ind is equipped with a Scully 8-track tape recorder ... a $6 million turnover in 1972. a 40 percent increase on figures
Step-by-step explanation:
Answer:
x>9 this is the correct answer
Answer: VIICCCXLVII
Don’t forget to mark me brainliest :)
It is C prob i need point lol i’m sorry
