(a) SSS (side side side)
every side on one triangle is correspondingly equal to that of the same side in the other triangle
Alright, we're in the home stretch here :) All you need to remember is that i² = -1. Otherwise, it is the same as FOIL
(3-2i)(1+7i)
3-2i+21i-14i² ← Replace the i² with -1, then simplify like numbers
3+19i+14
17+19i or C
F(-2) is the f(x) when x is -2. From the table, it is 1.
Answer:
<h3>See explanations below</h3>
Step-by-step explanation:
1) Given the recursive function An=an-1 + 3 when a1 = 5, we are to find the first four terms;
First term a1 = 5
a2 = a1 +3
a2 = 5 + 3
a2 = 8
a3 = a2 + 3
a3 = 8+3
a3 = 11
a4 = a3 + 3
a4 = 11 + 3
a4 = 14
<em>The first four terms are 5, 8, 11 and 14</em>
<em></em>
<em>2) </em>For the recursive function An=an-1 + 2/3 when a1 = 1
a2 = a1 + 2/3
a2 = 1 + 2/3
a2 = 5/3
a3 = a2 + 2/3
a3 = 5/3 + 2/3
a3 = 7/3
a4 = a3 + 2/3
a4 = 7/3 + 2/3
a4 = 9/3
a4 = 3
<em>Hence the first four terms of the sequence are 2/3, 5/3, 7/3, 3</em>
<em></em>
3) For the recursive function An=an-1 + 12 when a1=30
a2 = a1 + 12
a2 = 30 + 12
a2 = 42
a3 = a2 +12
a3 = 42 + 12
a3 = 54
a4 = a3 + 12
a4 = 54+12
a4 = 66
<em>Hence the first four terms of the sequence are 30, 42, 54, 66</em>
P is just a definition: it's the ratio between a circle's diameter and its circumference. In other words, any circle circumference is approximately 3.14 (p) times longer (around) than its diameter length. Some old Greek dude discovered it a few thousand years ago... Let's do the first 3 problems together - by then I think you'll have confidence you can do the remaining 3! 1. If C = 2pr, then we substitute C = 2*3.14*6, = 37.68 2. If C = 2pr, then let's rearrange that so we can find r: divide both sides (to keep it equal) by 2p to get r by itself: C/2p = 2pr/2p, so r = C/2p. Now substitute: r = 24p/2p = 12 3. If C = 2pr, then r = C/2p (see #2 above), then r = d/2. If A = pr2, then A = p (C/2p)2. Substitute: A = p (32p/2p)2, or A = p (16)2 A = 3.14 * 256 = 803.84 Now can you complete #3 - #6? I bet you can... :-)
