The sum of the two <em>rational</em> equations is equal to (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²).
<h3>How to simplify the addition between two rational equations</h3>
In this question we must use <em>algebra</em> definitions and theorems to simplify the addition of two <em>rational</em> equations into a <em>single rational</em> equation. Now we proceed to show the procedure of solution in detail:
- (n + 5) / (n² + 3 · n - 10) + 5 / (3 · n²) Given
- (n + 5) / [(n + 5) · (n - 2)] + 5 / (3 · n²) x² - (r₁ + r₂) · x + r₁ · r₂ = (x - r₁) · (x - r₂)
- 1 / (n - 2) + 5 / (3 · n²) Associative and modulative property / Existence of the multiplicative inverse
- [3 · n² + 5 · (n - 2)] / [3 · n² · (n - 2)] Addition of fractions with different denominator
- (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²) Distributive property / Power properties / Result
To learn more on rational equations: brainly.com/question/20850120
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There are different formulas for calculating the two types of compound events: Say A and B are two events, then for mutually exclusive events: P(A or B) = P (A) + P(B). For mutually inclusive events, P (A or B) = P(A) + P(B) - P(A and B).
I need 2 see the number line 2 know....
9514 1404 393
Answer:
∠KXN and ∠QXT
Step-by-step explanation:
The measure of each angle is the difference of the scale values that the rays intercept. (The same scale needs to be used for each ray.) Of course, complementary angles have a sum of 90°.
Here, we'll refer to angle aXb as "ab".
NP = 95 -35 = 60
PQ = 35 -20 = 15 . . . not complementary to NP
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KN = 165 -95 = 70
QT = 20 -0 = 20 . . . complementary to KN ⇒ your answer
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JK = 180 -165 = 15
PQ = 35 -20 = 15 . . . not complementary to JK
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JK = 15
NK = KN = 70 . . . not complementary to JK
Answer:
a
Step-by-step explanation:
You're trying to find the distance between D and E so u use the distance formula.
sqrt (a+b-b^2)+(c-c)^2=sqrt a^2=a
