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3 years ago

2+6g=11-3g solve for g

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

5 0

2+6g=11-3g
9g=9
g=1.............

storchak [24]3 years ago

4 0

2+6g=11-3g
-2+3g -2+3g
9g=9
--- ---
9. 9
G=1

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A cuboid with a volume of 924cm^3 has dimensions 4cm, (x+1)cm and (x+11). Show clearly that x^2+12x-220=0 solve the equation by

garik1379 [7]

Answer:

$x^2+12x-220=0$ -- Proved

$x = 10\ \ \ x = -22$

Step-by-step explanation:

Given

$Volume = 924cm^3$

$Dimension: 4cm; (x+1)cm; (x+11)cm$

Required

Show that $x^2+12x-220=0$

The volume is calculated as:

$4 * (x + 1) * (x + 11) = 924$

Open the brackets

$(4x + 4) * (x + 11) = 924$

$4x^2 + 44x + 4x + 44 = 924$

$4x^2 + 48x+ 44 = 924$

Collect Like Terms

$4x^2 + 48x+ 44 - 924=0$

$4x^2 + 48x -880=0$

Divide through by 4

$\frac{4x^2}{4} + \frac{48x}{4} -\frac{880}{4}=0$

$x^2+12x-220=0$

Solving further:

Expand the expression

$x^2 + 22x - 10x - 220 = 0$

Factorize:

$x(x + 22) - 10(x + 22) = 0$

$(x - 10)(x + 22) = 0$

Split:

$x - 10 = 0;\ \ \ x + 22 = 0$

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5 0

2 years ago

The area A of a triangle with base b and height h is given by A = = bh. Find the area when b = 18 m (meters) and h = 30 m.

Pie

Answer:

$Area = 270m^2$

Step-by-step explanation:

Given

$A = \frac{1}{2}bh$

$b = 18m$

$h = 30m$

Required

Solve for A

Simply substitute 18 for b and 30 for h

$A = \frac{1}{2}bh$

$A = \frac{1}{2} * 18 * 30$

$A = 270$

Hence:

The area is

$Area = 270m^2$

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3 years ago

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n200080 [17]

Answer:

0.1527

Step-by-step explanation:

Given that a researcher wishes to conduct a study of the color preferences of new car buyers.

Suppose that 50% of this population prefers the color red

15 buyers are randomly selected

Let X be the no of buyers who prefer red.

X has exactly two outcomes red or non red.

Also each buyer is independent of the other

Hence X is binomial with p = 0.5 and n = 15

Required prob =The probability that exactly three-fifths of the buyers would prefer red

= P(X=9)

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2 years ago

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Answer:

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Step-by-step explanation:

8y - 6y = 2y + 3y = 5y

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2 years ago

The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds

belka [17]

Answer:

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And we can find this probability with this difference:

$P(-0.6$

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

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Where $\mu=200$ and $\sigma=50$

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$P(170$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And using this formula we got:

$P(170$

And we can find this probability with this difference:

$P(-0.6$

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3 years ago