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Alexus [3.1K]
3 years ago
6

What is the minnimum value of the equation y=2x^2+5.

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0
The correct answer is 0.775255128608411.


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State whether the equation is true, false or open? 4y+8=6y+3
g100num [7]

<u><em>Answer:</em></u>

Open


<u><em>Explanation:</em></u>

An open equation is an equation that has variables and CAN be solved

<u>Example</u>: 2x = 4 ......> can be solved giving ......> x = 2

A false equation is one where both sides can NEVER be equal

<u>Example:</u> 15 = 2(3) + 1 ..........> 15 can never be equal to 7

A true equation is one having no variables and both sides are ALWAYS equal

<u>Example:</u> 2(3) + 1 = 2(2) + 3 ........> 7 will always be equal to 7


Now, the given equation is:

4y + 8 = 6y + 3

Let's try to solve is:

4y + 8 = 6y + 3

6y - 4y = 8 - 3

2y = 5

y = 2.5


Therefore, the given equation contains a variable and can be solved which means that it is an open equation


Hope this helps :)

8 0
2 years ago
Read 2 more answers
The sum of a number and its square is 182. Find the number.
Mars2501 [29]

Answer:

13 and -14 satisfy this condition

Step-by-step explanation:

Let's represent that number as x

and the square of x is x^2

So,

x + x^2 = 182

Subtract 182 from both sides

x + x^2 - 182 = 182 - 182

x + x^2 - 182 = 0

rearrange the quadratic equation

x^2 + x -182 = 0

let's use the quadratic formula

\frac{-b+\sqrt{b^2-4ac} }{2a}       or      \frac{-b-\sqrt{b^2-4ac} }{2a}

a = 1, b = 1, c = -182

\frac{-1+\sqrt{1^2-4*1*(-182)} }{2*1}       or     \frac{-1-\sqrt{1^2-4*1*(-182)} }{2*1}

\frac{-1+\sqrt{1+728} }{2}      or         \frac{-1-\sqrt{1+728} }{2}

\frac{-1+\sqrt{729} }{2}            or    \frac{-1-\sqrt{729} }{2}

\frac{-1+{27} }{2}     or    \frac{-1-{27} }{2}

\frac{26}{2}     or    \frac{-28}{2}

13 or    - 14

Lets check

13 + 13^2 = 13 + 169

= 182

Also,

-14 + (-14^2) = -14 + 196

= 182

8 0
3 years ago
$600is what percent of $1000
GrogVix [38]

Answer:

60%

Step-by-step explanation:

$600 as a percentage of $1000

= (600/1000) x 100%

= 60%

Hope this helps!

5 0
3 years ago
Read 2 more answers
How many arrangements can be made using 2 letters of the word HYPERBOLAS if no letter is to be used more than once?
alisha [4.7K]

Answer:

90 arrangements

Step-by-step explanation:

Since there are no repititions of letters, there are unique  10 letters in total.

THe number of arrangements would be 2 permutation 10. We need the formula for permutation. That is:

nPr=\frac{n!}{(n-r)!}\\

Now, n = 10 [total] and r is 2, so we have:

nPr=\frac{n!}{(n-r)!}\\\\_{10}P_{2}=\frac{10!}{(10-2)!}\\=\frac{10!}{8!}\\=\frac{10*9*8!}{8!}\\=10*9\\=90

So, there can be 90 arrangements

3 0
3 years ago
Kendra has $ 7.75 $7.75 in nickels and quarters. if she has 13 13 more quarters than nickels, how many of each coin does she hav
Ludmilka [50]
Total of $7.75
13 more quarters than nickels

15 nickels = $0.75
28 quarters = $7.00

28 - 15 = 13 coins
$7.00 + $0.75 = $7.75


She has 15 nickels and 28 quarters.
7 0
3 years ago
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