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PIT_PIT [208]
2 years ago
15

What is breaking probation?

Mathematics
1 answer:
masha68 [24]2 years ago
7 0

Answer:

a probation violation occurs when someone who has already been sentenced for a crime breaks the terms or conditions of that probation

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PLEASE HELPPP I WILL MARK BRAINLIEST
Rina8888 [55]

Answer: they are different the difference is 28

Step-by-step explanation:

6 0
2 years ago
6m+10p when m=8 and p=14
Luba_88 [7]

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3 years ago
Read 2 more answers
Suppose a circle with center (14,9) passes through point (16, 12). Which equation represents the circle?
kifflom [539]

Answer:

( x - 14)^2 + ( y - 9)^2 = 13

Step-by-step explanation:

The equation of the circle with a center and a point

( x - a) ^2 + ( y - b) ^2 = r^2

( 14 , 9) - center-( a, b)

a = 14

b = 9

( 16 , 12) - point - ( x, y)

x = 16

y = 12

Step 1: substitute the center into the equation

( x - 14)^2 + ( y - 9)^2 = r^2

Step 2: substitute the point into the equation

( x - 14)^2 +( y - 9)^2 = r^2

( 16 - 14)^2 + ( 12 - 9)^2 = r^2

2^2 + 3^2 = r^2

4 + 9 = r^2

13 = r^2

Step 3: subs the radius into the equation

( x - 14)^2 + ( y - 9)^2 = r^2

( x - 14)^2 + (y - 9)^2 = 13

Therefore, the equation of the circle is

( x - 14)^2 + ( y - 9)^2 = 13

8 0
3 years ago
While in France, Judy wants to sign up for a bike tour to see the countryside. She likes a tour that is 40 kilometers long, but
Sonja [21]

Answer:

24 miles

Step-by-step explanation:

In order to calculate Judy's estimation, we would simply have to multiply the actual distance in kilometers of the tour by the number of miles that Judy believes are in a single mile. This would give us Judy's estimation for how long the tour would be in miles.

40 km. * 0.6 miles = 24 miles

Finally, we can see that Judy's estimation would be that the tour is 24 miles long. Using Judy's believed conversion rate.

8 0
3 years ago
Given f(x)= 2x²+4x-6 and g(x)=2x-2, find each function
valkas [14]
F(x)= 2x²+4x-6 and g(x)=2x-2, find each function
1. (f/g) (x) = f(x)÷g(x) = (2x²+4x-6)÷(2x-2)
First factor both top and bottom:
(2x-2)(x+3)÷(2x-2) = x+3

2. f(a + 2) = plug (a+2) in anywhere there is an x in f(x)=2x²+4x-6 -->
2(a+2)^2 +4(a+2)-6 = 2(a^2+4a+4)+4a+8-6, now distribute:
2a^2+8a+8+4a+2, combine like terms
2a^2+12a+10

3. g(a/2) = plug (a/2) in anywhere there's an x in g(x)=2x-2:
2(a/2)-2 = a-2
5 0
3 years ago
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