Answer:
given
p=q^3
p=40
______
q=(p)^1/3
q=(40)^1/3-->q=2(5)^1/3
Now
the value of half of q , (2(5)^1/3)÷(2) ,is 5^1/3.
finally the value of p gonna be
p=q^3
p=(5^1/3) ^ 3
p=5
The value of f[ -4 ] and g°f[-2] are 
and 13 respectively.
<h3>What is the value of f[-4] and g°f[-2]?</h3>
Given the function;
- f[ -4 ] = ?
- g°f[ -2 ] = ?
For f[ -4 ], we substitute -4 for every variable x in the function.
For g°f[-2]
g°f[-2] is expressed as g(f(-2))
![g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13](https://tex.z-dn.net/?f=g%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%2B%205%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%20%2B%20%5Cfrac%7B5%28x%2B1%29%7D%7Bx%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B3x-2%2B5%28x%2B1%29%7D%7Bx%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B8x%2B3%7D%7Bx%2B1%7D%5C%5C%5C%5CWe%5C%20substitute%20%5C%20in%20%5C%20%5B-2%5D%20%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B8%28-2%29%2B3%7D%7B%28-2%29%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B-16%2B3%7D%7B-2%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B-13%7D%7B-1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%2013)
Therefore, the value of f[ -4 ] and g°f[-2] are and 13 respectively.
Learn more about composite functions here: brainly.com/question/20379727
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Answer:
6 (2)^ = 6
6 (2)^2 = 24
a = 24
b = 6
y-intercept: (0,6)
y-intercept =
Step-by-step explanation:
6(2)^x
6 (2)^0 = 6 (a number ^0 = 1, 6 times 1 = 6)
6 (2)^2 = 6 x 4 = 24
Answer:
1. 41/45.
2. x/(x^2+3x+6)
Step-by-step explanation:
1.
So first we fill the ven diagram.
There are 240 in band, so we fill that. 60 students are in both, we put that in the middle, and there are 110 people in choir.
now, since we want the probability that a student is chosen that is in band, and choir, and both. We add all this up
240 + 60 + 110 = 410.
The total possible outcome is 410, and the total outcome is 450, so the answer is
410/450 = 41/45
2.
First, to get the total outcomes, we have to add all the expressions together.
x(x-2) + x + 2x+8 = x^2 - 2 + x + 2x + 8 = x^2 - 2 + 3x + 8 = x^2 + 3x + 6.
Since that is the total outcome, we have to find the possible outcomes.
The problem wants BOTH from the 20th century and British, so it is x.
x/(x^2+3x+6). We cannot simplify any further, thus x/(x^2+3x+6) is our answer
