Question

LoL i need help with this question oof

Answer 1

Given expression:

$\sqrt[5]{(n+4)^{3}}$

To find:

The equivalent expression.

Solution:

$\sqrt[5]{(n+4)^{3}}$

Apply radical rule:

$\sqrt[m]{a}=a^{\frac{1}{m}}$

Using this rule in the given expression:

$\sqrt[5]{(n+4)^{3}}=\left((n+4)^{3}\right)^{\frac{1}{5}}$

Apply exponent rule:

$\left(a^{b}\right)^{c}=a^{b c}$

Using this rule:

$\left((n+4)^{3}\right)^{\frac{1}{5}}=(n+4)^{3 \cdot \frac{1}{5}}$

On multiplying 3 and $\frac{1}{5}$, we get $\frac{3}{5}$.

                  $=(n+4)^{\frac{3}{5}}$

The equivalent expression for the given expression is $(n+4)^{\frac{3}{5}}$.

Answer 2

Answer:

D

Step-by-step explanation:

5 on the radical is basically power ⅕

[(n+4)³]^⅕

(n+4)^⅗