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4 years ago

All right angles are _____ degrees

Mathematics

1 answer:

babymother [125]4 years ago

7 0

I think the answer is 90 degrees

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Yellow Taxi Cabs charges a $7 flat rate in addition to $2.25 per mile. Kate has $100 to spend on transportation. How many miles

enyata [817]

Kate can travel 41.33 miles without exceeding her limit. This problem can be solved by using y = 2.25x + 7 linear equation with the "y" variable as the total cost that Kate must pay after she has traveled with the cab and the "x" variable as Kate's traveling distance. The equation has 7 for its constant value which is the $7 flat rate. We will find 41.33 miles as the traveling distance if we substituted the total cost with 100, which is the maximum amount that can be paid by Kate for the traveling purpose.

7 0

3 years ago

-1/5y+7=7 What is the value of y?

liq [111]

The answer is y=0

See the attached photo for details

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.

8 0

3 years ago

Write a quadratic function with zeroes 0 and 8.

Jlenok [28]

Answer:

$x^2-8x=0$

Step-by-step explanation:

the quadratic function should be as follows:

$x^2-8x=0$

Now let's confirm that the zeros of the function are 0 and 8

$x^2-8x=0=x(x-8)=0$

Therefore we can see that if x = 0

$0^2*8*0=0\\0=0$

the equation is fulfilled

And we also have $(x-8)$

for this expresion to be equal to zero:

$x-8=0\\x=8$

thus, if x = 8

$8^2-8*8=0\\64-64=0\\0=0$

the equation is also fulfilled

The zeros of the quadratic function $x^2-8x=0$ are 0 and 8.

3 0

3 years ago

For the function f(x) = x + 7, what is the ordered pair for the point on the graph when x = 2b. A. ( 2b, 2b+7). B. ( 2b, x + 7).

Fynjy0 [20]

$f(2b)=2b+7\\\\
(2b,2b+7)$

6 0

3 years ago

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Given the function f(x) = x3 + 2x2 − 3x − 5, what is resulting function when f(x) is shifted to the right 1 unit?

cluponka [151]

When shifted to the right 1 unit it would be:
f(x - 1) = (x - 1)^3 + 2(x - 1)^2 - 3(x - 1) - 5
= (x^3 - 3x^2 + 3x - 1) + 2(x^2 - 2x + 1) - 3(x - 1) - 5 
= x^3 - 3x^2 + 2x^2 + 3x - 4x - 3x - 1 + 2 + 3 - 5 
= x^3 - x^2 - 4x - 1
I hope this helps

5 0

3 years ago

Read 2 more answers