Question

Trent train is traveling at the speed of 10m/s at the top of a hill. Five seconds later it reaches the bottom of the hill and is moving at 39 m/s. What is the rate of acceleration of Trent train?

Answer 1

Answer:

5.8ms^2

Step-by-step explanation:

Answer 2

The first thing to do before starting to solve any numerical is to write down all the information we have.

Initial speed (u) = 10 m/s

Final speed  (v) = 39 m/s

Time (t) = 5 seconds

To find acceleration(a):

We know the equation for the first Law of Motion:

v = u+a*t

Hence, we can rearrange this as:

a = (v-u)/t

On substituting the values given,

a = (39 - 10)/5

a = 29/5

a = 5.8 m/(s^2)

Hence, the acceleration of the train is 5.8 m/(s^2)