Total students = 28
Students with brown eyes = 19
students wear glasses = 13
Not brown eyes or no glasses = 7
Not brown eyes = 28 - 19 = 9
Not wearing glasses = 28 - 13 = 15
Not brown eyes and wearing glasses = 15 - 9 = 6
Brown eyes and wearing glasses = 13 - 6 = 7 <==== answer
I am not 100% sure this is right but I believe its 28:)
Answer:
d. 0.0948 ± 4.032(0.0279)
Step-by-step explanation:
A 99% confidence interval for the coefficient of promotional expenditures is, First, compute the t critical value then find confidence interval.
The t critical value for the 99% confidence interval is,
The sample size is small and two-tailed test. Look in the column headed es = 0.01 and the row headed in the t distribution table by using degree of freedom is here
for (n-2=5) degree of freedom and 99% confidence ; critical t =4.032
therefore 99% confidence interval for the slope =estimated slope -/+ t*Std error
= 0.094781123 -/+ 4.032* 0.027926367 = -0.017822 to 0.207384
Answer:
2^4
Step-by-step explanation:
2*2*2*2
There are four 2's multiplied together
2 is the base and 4 is the exponent
2^4
4,003,052 is the answer to the problem