3 years ago

Need help finding PT

Mathematics

1 answer:

Fantom [35]3 years ago

4 0

C-26.5 is the answer I think hope it helped

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Find the slope of the line passing through the points (-6,2), (0,-6).

Serhud [2]

C. -4/3

$slope = \frac{(y _{2} - y _{1}) }{(x _{2} - x _{1} )} \\ = \frac{( - 6 - 2)}{(0 -( - 6)} \\ = \frac{ - 8}{ 6} \\ = - \frac{4}{3}$

3 0

3 years ago

Log (3x+1) - Log (2x+5)= 1

sleet_krkn [62]

Answer:

$\huge \red { \boxed{x = - \frac{49}{17}}}$

Step-by-step explanation:

$log(3x + 1) - log(2x + 5) = 1 \\ \\ log \: \frac{3x + 1}{2x + 5} = log \: 10..( \because \: log \: 10 = 1) \\ \\ \frac{3x + 1}{2x + 5} = 10 \\ \\ 3x + 1 = 20x + 50 \\ 3x - 20x = 50 - 1 \\ \\ - 17x = 49 \\ \\ x = \frac{49}{ - 17} \\ \\ \huge \purple{ \boxed{x = - \frac{49}{17}}} \\$

6 0

3 years ago

Simplify 8(xy + 8) + 1.

kobusy [5.1K]

Look at the picture.

I hope this helps!

5 0

3 years ago

Read 2 more answers

Jeff is purchasing a car for $29,175 that will depreciate in value 7.5% each year.

beks73 [17]

Answer:

Step-by-step explanation:

figure that S*** out your self jeez

5 0

3 years ago

he graph represents function 1, and the equation represents function 2: A coordinate plane graph is shown. A horizontal line is

Reika [66]

Answer:

The answer is 2

Step-by-step explanation:

Rate of change of function is given by :

$\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}$

For function y = 6,

rate of change =

$=\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}\\=\frac{6-6}{x_{2}-x_{1}}\\=0$

because the function is independent of x.

For function y = 2·x + 7,

rate of change =

$=\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}\\=\frac{2\cdot x_{2}+7-2\cdot x_{1}-7}{x_{2}-x_{1}}\\=\frac{2\cdot x_{2}-2\cdot x_{1}}{x_{2}-x_{1}}\\=\frac{2\cdot (x_{2}-x_{1})}{x_{2}-x_{1}}\\=2$

So, the rate of change of 2 is greater than rate of change of function 1 by 2 - 0 = 2.

8 0

3 years ago