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AlladinOne [14]
3 years ago
15

What is the radius of the circle x2+y2=12

Mathematics
1 answer:
valkas [14]3 years ago
7 0

Answer:

Step-by-step explanation:

x²+y²=r²

r²=12

r=√12=2√3

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Edger needs 6 cookies and 2 brownies for every 4 plates how many cookies and brownies does he need for 10 plates
evablogger [386]

Answer:

Edger needs 15 cookies and 5 brownies.

Step-By-Step:

6 + 6 + 3 = 15

2 + 2 + 1 = 5

4 can go into 10, 2.5 times

6 0
3 years ago
Why are and Iby 4<br>and - 1 zeroes of the polynomial p(x) <br>= 4² +3x-1?​
Serggg [28]

Answer:

- 1 = 16 + 3x - 1 \\ 3x = 16 - 1 + 1 \\  \frac{3x}{3} =  \frac{16}{3}  \\  x = 5.33

7 0
3 years ago
PLEASE HELP WILL MARK BRAINLEIST
horsena [70]

Answer:

The picture shows the answer on the graph

Step-by-step explanation:

-2=-3/4×(x-6)

Distribute -3/4 through the parenthesis

-2= -3/4x+9/2

Multiply both sides of the equation by 4

-8=-3x+18

Move the variable to the left side and change its sign

3x-8=18

Move constant to the right side and change its sign

3x=18+8

Add the numbers

3x=26

Divide both sides of the equation by 3

x=26/3

Alternative Form- x=8 2/3 or x=8.6

7 0
3 years ago
Question 3(Multiple Choice Worth 4 points) (05.05)The width of a rectangle is shown below: A coordinate plane with a point A at
olganol [36]
D 4/147
FTC +65-/325
Junk. 5(-4)
8 0
3 years ago
A company has 7 male and 9 female employees, and needs to nominate 2 men and 2 women for the company bowling team. How many diff
lys-0071 [83]

Answer:

The team can be formed in 756 different ways

Step-by-step explanation:

This is a combination problem since we are to select a set of people from a group. Combination has to do with selection.

for example, if r number of object is to be selected from a pool of n objects, this can be done in nCr number of ways.

nCr = \frac{n!}{(n-r)!r!}

Now If A company has 7 male and 9 female employees, and needs to nominate 2 men and 2 women for the company bowling team, then this can be done in the following way;

7C2 * 9C2

7C2 = \frac{7!}{5!2!} \\= \frac{7*6*5!}{5!*2} \\= 7*3\\= 21ways\\\\similarly;\\\\9C2 = \frac{9!}{7!2!}\\9C2= \frac{9*8*7!}{7!*2} \\9C2 = 9*4\\9C2 = 36

7C2 * 9C2 = 21*36

= 756

The team can be formed in 756 different ways

5 0
3 years ago
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