Answer: what’s the rest of the question? You didn’t provide enough data…✨
Step-by-step explanation:
Current amount in account
P=36948.61
Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n
Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11
We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000
We can solve this by trial and error.
The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000. It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.
So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.
So it takes 15.00 years to reach the goal of 280000 years.
Answer:
The correct answer is second option option
9¹/⁸ ˣ
Step-by-step explanation:
<u>Points to remember</u>
<u>Identities</u>
ᵃ√x = = x¹/ᵃ
√x = x¹/²
(xᵃ)ᵇ = xᵃᵇ
<u>To find the correct option</u>
It s given that,
(⁴√9)¹/² ˣ
By using the above identities we can write,
(⁴√9)¹/²ˣ = (9¹/⁴)¹/²ˣ [ since ⁴√9 = 9¹/⁴]
= 9⁽¹/⁴ * ¹/²⁾ ˣ
= 9¹/⁸ ˣ
Therefore the correct answer is second option option
9¹/⁸ ˣ
