THIS IS THE COMPLETE QUESTION BELOW;
The weekly salaries of sociologists in the United States are normally distributed and have a known population standard deviation of 425 dollars and an unknown population mean. A random sample of 22 sociologists is taken and gives a sample mean of 1520 dollars.
Find the margin of error for the confidence interval for the population mean with a 98% confidence level.
z0.10 z0.05 z0.025 z0.01 z0.005
1.282 1.645 1.960 2.326 2.576
You may use a calculator or the common z values above. Round the final answer to two decimal places.
Answer
Margin error =210.8
Given:
standard deviation of 425
sample mean x=1520 dollars.
random sample n= 22
From the question We need to to calculate the margin of error for the confidence interval for the population mean .
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION
Answer:
37/6
Step-by-step explanation:
-23/6 - 7/3
= -23/6 - 14/6 just make both have the same denominator (2x the 3 to make 6 and do same with numerator)
= 37/6 or 6 1/6
Q55.
UTA+ATS=UTS
x+18+120=12x+17
x+138=12x+17
12x-x=138-17
11x=121
x=121/11
x=11
mUTA=x+18
put the value of x
11+18
mUTA=29
Q57.
AQP+RQA=RQP
9x+2+75=1+28x
9x+77=1+28x
28x-9x=77-1
19x=76
x=76/19
x=4
mRQP=1+28x
put the value of x
1+28(4)
1+112
mRQP=113
Answer:
Independent Sampling
Step-by-step explanation:
There are two scenarios for independent sampling .
Testing the mean we get the differences between samples from each population. When both samples are randomly inferences about the populations. can get.
Independent sampling are sample that are selected randomly. Observation does not depend upon value.Many analysis assume that sample are independent.
In this statement 90 dash are divides into two groups Group 1 and Group 2 . Both are standardized that mean both are randomly selected. Means are observed. Observation doesn't depend upon value. So this style of sampling is independent Sample.
Let the two integers be x and x+1
(x+1)^2-x^2=21
x^2+2x+1-x^2=21
2x+1=21
2x=20
x=10
then x=10, x+1
10+1=11
the two integers are 10, 11
