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sergeinik [125]
4 years ago
13

Solve the quadratic equation by completing the square.

Mathematics
1 answer:
cupoosta [38]4 years ago
7 0

Answer:

A

Step-by-step explanation:

x² - 10x + 18 = 0

x² - 2(x)(5) + 5² - 5² + 18 = 0

(x - 5)² = 7

x = 5 + sqrt(7), 5 - sqrt(7)

sqrt: square root

You might be interested in
Question 2 (1 point)
vlada-n [284]

(3,0)

Step-by-step explanation:

Different - add

2x - y = 6

+

x + y. = 3

3x = 9

÷3

x = 3

Substitute x = 3 into one of the equation:

x + y = 3

3 + y = 3

-3

y = 0

Solution is (3,0)

Hope this helps!

4 0
2 years ago
Marcia is given ZAB shown below.
bulgar [2K]
B is the answer to the question
6 0
3 years ago
4.(06.02 MC)
miss Akunina [59]

Answer:

The equation of a parallel line in the slope-Intercept form that contains the point (3,-2) is:

  • y = 2x- 8

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the equation of a line

y = 2x + 4

comparing with the slope-intercept form of the line equation

The slope of the line AB is m = 2

We know that the parallel lines have the same slope.

Thus, the slope of the new line is also 2.

now we have,

  • The slope of new line m = 2
  • The point = (3, -2)

Using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

substituting the values m = 2 and the point (x₁, y₁) =  (3, -2)

y-y_1=m\left(x-x_1\right)

y - (-2) = 2(x - 3)

y + 2 = 2x - 6

subtracting 2 from both sides

y + 2 - 2 = 2x - 6 - 2

y = 2x- 8

Therefore, the equation of a parallel line in the slope-Intercept form that contains the point (3,-2) is:

  • y = 2x- 8
6 0
3 years ago
Is 6 a diviser of 84
Nata [24]
Yes because 84/6 = 14!!!
6 0
3 years ago
The coordinates of both the pre-image and image of quadrilateral JKLM are listed in the table
pychu [463]

Answer:

Option C.

Step-by-step explanation:

From the table attached,

Pre-image coordinates J(-8, 2) → Image coordinates J'(-22, 5.5)

J(-8, 2) → J'(-22, 5.5)

Since, rule for the dilation of a point is,

(x, y) → (kx, ky) [Here k = scale factor of dilation]

Therefore, kx = -22

k(-8) = -22

k = \frac{-22}{-8}

k = 2.75

So the scale factor should be 2.75

From the given options,

Option A.

(x, y) → \frac{4}{11}(x, y)

       → 0.36(x, y)

But value of k should be 0.36

Therefore, Incorrect option.

Option B.

(x, y) → \frac{3}{22}(x, y)

       → 0.14(x, y)

k = 0.14

But the value of k should be 2.75

Incorrect option.

Option C.

(x, y) → \frac{11}{4}(x, y)

       → 2.75(x, y)

k = 2.75

Therefore, this option is correct.

Option D.

(x, y) → \frac{22}{3}(x, y)

       → 7.33(x, y)

k = 7.33

But the scale factor should be 7.33

Incorrect option.

8 0
3 years ago
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