3 medium cars to 1 small car can be made into a fraction like this: $\frac{3}{1}$ or $\frac{1}{3}$ . But you must be consistent if the denominator represents medium cars or small cars.

For this, I'm just going to make medium cars the numerator.

18 medium cars to 6 cars can be made into a fraction like this : $\frac{18}{6}$ .

When you divide both fractions in a calculator (or in your head), you will realize that they both are the same value (equivalent).

$\frac{3}{1}=\frac{18}{6} = 3$

$\frac{1}{3} = \frac{6}{18} = .3333333$

These ratios are equivalent.

4 0

3 years ago

Describe the nature of the roots for this equation.

kirza4 [7]

Answer:

Option D. two complex roots

Step-by-step explanation:

we know that

In a quadratic equation of the form $ax^{2} +bx+c=0$ the discriminant D is equal to

$D=(b^{2}-4ac)$

in this problem we have

$3x^{2} -2x+1=0$

$a=3\\b=-2\\c=1$

substitute the values

$D=(-2^{2}-4(3)(1))$

$D=(4-12)$

$D=-8$

The discriminant is negative

therefore

The quadratic equation has two complex roots

5 0

3 years ago