3 years ago

What is the product (y+3)(y^2-3y+9)

Mathematics

1 answer:

shutvik [7]3 years ago

8 0

Answer:

y^3 + 3^3

Step-by-step explanation:

1) Multiply each term of (y^2-3y+9) by y: y^3 - 3y^2 + 9y

2) Multiply each term of (y^2-3y+9) by 3: 3y^2 - 9y + 27

3) Add all of these terms together: y^3 + 27 = y^3 + 3^3

Note: this is an example of 'special products and factoring.'

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