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KiRa [710]
3 years ago
15

A company has two large computers. The slower computer can send all the company's email in 60 minutes. The faster computer can c

omplete the same job in 40 minutes. If both computers are working together, how long will it take them to do the job? Do not do any rounding.
Mathematics
1 answer:
Lelu [443]3 years ago
4 0

Answer:

If both computers are working together, it will take 24 minutes to do the job

Step-by-step explanation:

It is given that,

There are two computers.The slower computer can send all the company's email in 60 minutes.

The faster computer can complete the same job in 40 minutes

<u>To find the LCM of 40 and 60</u>

LCM (40, 60) = 120

<u>To find efficiency of 2 computers</u>

Let x be the efficiency of faster computer and y be the efficiency of faster computer

x = 120/40 = 3

y = 120/60 = 2

then, x + y = 3 + 2 = 5

Therefore efficiency of both the computer work together = x + y =5

<u>To find the time taken to work both the computer together</u>

time = 120/5 = 24 minutes

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$1200

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$4000 x .06 = $240 x 5 years = $1200

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3 years ago
If m1 = 70 what is m8?
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6 0
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What is the general process for solving an equation with one variable?
elena55 [62]
Greetings!

"<span>What is the general process for solving an equation with one variable?"...

Typically when solving an equation with one variable, your objective is to isolate the variable on one side of the equation. This can be done adding/subtracting number to cancel them out on one side. You can also multiply/divide coefficients in order to isolate a variable.

Example:
</span>2x+4=64
<span>Add -4 to both sides to isolate the variable.
</span>(2x+4)+(-4)=(64)+(-4)<span>
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Divide both sides by 2 to isolate the variable on one side.
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Hope this helps.
-Benjamin
5 0
3 years ago
A study of peach trees found that the average number of peaches per tree was 725. The standard deviation of the population is 70
TEA [102]

Answer:

She needs to sample 189 trees.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation of the population is 70 peaches per tree.

This means that \sigma = 70

How many trees does she need to sample to obtain an average accurate to within 10 peaches per tree?

She needs to sample n trees.

n is found when M = 10. So

M = z\frac{\sigma}{\sqrt{n}}

10 = 1.96\frac{70}{\sqrt{n}}

10\sqrt{n} = 1.96*70

Dividing both sides by 10:

\sqrt{n} = 1.96*7

(\sqrt{n})^2 = (1.96*7)^2

n = 188.2

Rounding up:

She needs to sample 189 trees.

3 0
3 years ago
If the unit selling price is $2.50 and the unit cost is $1.00, what action is needed to maintain the gross margin percentage whe
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5 0
3 years ago
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