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finlep [7]
3 years ago
5

A city that had 8000 thousand people at the beginning of the year 2000 has been decreasing by 3.2% per year. What is the 1-year

percent change in the city's population?
Mathematics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

7,744 (96.8% of population at the beginning of the year)

Step-by-step explanation:

Population of the city at the beginning of the year = 8000people

Yearly percentage decrease = 3.2%

This means at the end of the first year the population reduces by 3.2% which gives 3.2%of 8000

= 3.2/100 × 8000

= 3.2 × 80

= 256

This shows that the population decreases by 256 at the end of first year.

To get the 1year percentage change in population, we will subtract the percentage decrease in Population from the initial population to give;

8000 - 256

= 7,744

7,744population remains after 1year wish is (100-3.2)% i.e 96.8% of the population at the beginning of the year.

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645 plus 763 to the nearest hundredth
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Answer:

1408

What you have to do is 645 + 763 = 1408 that's how you doing I think so and sorry if I did it wrong

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Using the scale given 1cm = 8km. Hatboro and Smithville are 24cm apart on the map. What is their actual distance (km) between th
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Answer:

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3 years ago
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(take π=22/7). height of trapezium with parallel sides 6cm and 8cm and 63cm2.​
Nataly_w [17]

Answer:

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Also,

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Step-by-step explanation:

<em>#</em><em>C</em><em>arryOnLearning</em>

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I give you brailenst
Ostrovityanka [42]

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The answer is #3 which is 24%.

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I really hope this helps :)

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