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finlep [7]
3 years ago
5

A city that had 8000 thousand people at the beginning of the year 2000 has been decreasing by 3.2% per year. What is the 1-year

percent change in the city's population?
Mathematics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

7,744 (96.8% of population at the beginning of the year)

Step-by-step explanation:

Population of the city at the beginning of the year = 8000people

Yearly percentage decrease = 3.2%

This means at the end of the first year the population reduces by 3.2% which gives 3.2%of 8000

= 3.2/100 × 8000

= 3.2 × 80

= 256

This shows that the population decreases by 256 at the end of first year.

To get the 1year percentage change in population, we will subtract the percentage decrease in Population from the initial population to give;

8000 - 256

= 7,744

7,744population remains after 1year wish is (100-3.2)% i.e 96.8% of the population at the beginning of the year.

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Tatiana [17]

Answer:

3 3/7 or 24/7 mins

Step-by-step explanation:

Let total job = X

Jeff's rate = X/6

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Shortcut:

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T = (6×8)/(6+8)

T = 48/14

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8 0
3 years ago
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chubhunter [2.5K]

Answer:

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3 0
3 years ago
Need help with both questions please
Inessa [10]
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A new car loses 18% of its value in a year. At a year old, it is worth
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Step-by-step explanation:

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