Answer:
1. z^2
2. 14z
Step-by-step explanation:
- We know that (a^m)^n = a^(mn) = (a^n) ^m
We also know that (a^m)(a^n) = a^(m+n)
- 36 can be written as 6^2 and here 36^(500) can be written as (6^2)^500 which also can be written as (6^500)^2 and as already it is mentioned that 6^500 as z we can write the above as <u>z^2</u>
2. 8 x 6^500 = 8z
And we can also write 6^(501) as 6^(500+1) which is equivalent to 6(6^500) which is 6z.
From the above we can make sure that the question is the sum of the above which is 8z + 6z = <u>14z</u><u>.</u>
Answer:
1. 8
2. 4
3a. -6 and -4
3b. -1/2 and -5
Step-by-step explanation:
3a explanation:
Factor x^2+10x+24
(x+4)(x+6)
Set the factors equal to 0
x + 4 = 0
x + 6 = 0
-4 and -6
3b.
Factor left side of equation.
(2x+1)(x+5)=0
Set factors equal to 0.
2x + 1 = 0 or
x + 5 = 0
x = −1/2
x = -5
-5 and -1/2
Answer:
8:16 and 7:14
Step-by-step explanation:
5:10 is a 1 to 2 ratio and so are 8:16 and 7:14
Answer:
G= -2/x, x 
0
X= -2/g, g 0
Step-by-step explanation:
Answer:
The maximum amount of money the chemistry club can spend without going over their buget is $81.4 ... With a total of 6 hours their allowed to use the room for.
Step-by-step explanation:
$49 is our constant and will not change. 5.40 however will. Let's use variable h for the amount hours they can rent the room for. Now we can make an inequality;
49+ 5.40h < 86.80
5.40h < 86.80
5.4h< 37.8
h< 7
Now that we know h will have to be less than seven for the chemistry club to spend less than their buget we can find that 6 is the maxium amount of hours they can spend in the room while staying within their budget.
(This answer does not consider decimals or half hours)
