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elena-s [515]
4 years ago
13

Solve 54=y−14 please help meeeeee

Mathematics
1 answer:
Inessa05 [86]4 years ago
5 0

Answer:

y=68

Step-by-step explanation:

54=y−14

54+14=y

68=y

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Find the area of the circle. Round your answer to the nearest hundredth
scZoUnD [109]

Answer:

Step-by-step explanation:

Area = pi r^2      if 3 is the radius

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if 3 is the diameter then radius = 1.5

     pi r^2 = pi (1.5)^2    in^2

5 0
3 years ago
PLEASE HELPP MEEE<br> x / 3 &lt; 2
Eduardwww [97]

Answer:

3

Step-by-step explanation:

3/3=1 which is smaller then 2

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Read 2 more answers
PLEASE HELP WITH PART B!!<br><br> can you also explain y and x, I dont understand part B &gt;
Doss [256]

A. I would suggest including <em>all</em> units in your answer. Both answers are correct but the unit is also important.

average rate of change:

($750 - $350) / (2014 - 2010) = $400 / (4 years) = $100 per year

initial value:

$350

B. Take 2010 to be year 0. Then for year <em>x</em> = 0, the fee is <em>y</em> = $350.

If the fee increases at a rate of $100 per year, this means that when <em>x</em> = 1, <em>y</em> = $350 + $100 = $450. So the graph of the function that models the dog-walking fee is a line that passes through the points (0, 350) and (1, 450), adn the slope of this line is

(450 - 350) / (1 - 0) = 100/1 = 100

which is the same as the average rate of change.

Using the point-slope formula for a line, the equation you want is then

<em>y</em> - 350 = 100 (<em>x</em> - 0)

<em>y</em> - 350 = 100<em>x</em>

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8 0
3 years ago
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Ronch [10]
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4 0
3 years ago
How many real roots would f(x)=<br> x^3+2x^2+2x-5 have
goldfiish [28.3K]

Answer:

One real root

Step-by-step explanation:

By the fundamental theorem of algebra, an nth degree polynomial has n-possible real roots.

If there are complex roots, then the the complex roots come in pairs.

Therefore the number of possible real roots of f(x)=x^3+2x^2+2x-5 are 3 real roots with no complex pairs or 1 real root with a complex pair.

By Descartes rule of signs, there is only one change of sign in the polynomial (+ to -).

Hence there is only one positive real root.

f(-x)=-x^3+2x^2-2x-5

There is change is sign two times but we can not have even number of real roots for this polynomial

Therefore there is only real root.

7 0
4 years ago
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