Answer:
(a) The 26th percentile for the number of chocolate chips in a bag is 1185
(b) The number of chocolate chips in a bag that makes up the middle 96% of the bags is between 1020 and 1504
Step-by-step explanation:
From the question, we have the following values:
μ =1262 and σ =118
(a) Let the value of x represents the 26th percentile. So the 26th percentile means 26% data is less than x. We can use the standard normal table to get the particular z-value that corresponds to this percentile.
P( Z<-0.65 )=0.2578 which is approximately 0.26
So for 26th percentile z-score will be -0.65.
Mathematically;
z-score = (x-mean)/SD
-0.65 = (x-1262)/118
-76.7 = x -1262
x = 1262-76.7 = 1185.3
This value is approximately 1,185
(b) Using a graph of standard normal distribution curve, if middle is 96% , then at both tails 2% each.
From z-table, we can find the closest probability;
P(-2.05<z<2.05) = 0.96
So we have two x values to get from the individual z-scores
-2.05 = (x-1262)/118
x = 1020(approximately)
For 2.05, we have
2.05 = (x-1262)/118
x = 1262 + 2.05(118) = 1504 (approximately)
Answer:
see below
Step-by-step explanation:
a)
minimum = 45
first quartile = 55
median = 75
third quartile = 85
maximum = 95
lower fence = Q1 - 1.5 x IQR = 10
upper fence = Q3 + 1.5 x IQR = 130
Therefore, one outlier = 140
b) mean = sum of all numbers ÷ n = 760 ÷ 10 = 76 ($76,000)
There is an outlier (140). Outliers don't affect the median as much as they affect the mean.
c) see attached
d) negative skew
Do you mean ones and tenths?
the correct answer it's equation D