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GuDViN [60]
3 years ago
13

The sales record of a real estate company for the month of May shows the following house prices (rounded to the nearest $1,000).

Values are in thousands of dollars. 140 55 45 85 75 50 60 75 80 95
(a) Find the five-number summary for the house prices. Five-number summary
(b) Find the mean. Explain why the mean and median are different for this particular set of data.
(c) Construct a labeled boxplot for the house prices. (Show all your work). 40 50 60 70 80 90 100 110 120 130 140 150
(d) Describe the distribution of the house prices.
Mathematics
1 answer:
Semenov [28]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

a)

minimum = 45

first quartile = 55

median = 75

third quartile = 85

maximum = 95

lower fence = Q1 - 1.5 x IQR  = 10

upper fence = Q3 + 1.5 x IQR  = 130

Therefore, one outlier = 140

b)  mean = sum of all numbers ÷ n = 760 ÷ 10 = 76  ($76,000)

There is an outlier (140). Outliers don't affect the median as much as they affect the mean.  

c) see attached

d) negative skew

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Pepsi [2]
X=4
Step 1: Simplify both sides of the equation.
1.5(x+4)-3=4.5(x-2)
(1.5)(x)+(1.5)(4)+ -3 =(4.5)(x)+(4.5)(-2)
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1.5x+3=4.5x-9

Step 2: Subtract 4.5x from both sides.
1.5x +3 -4.5x =4.5x=-9-4.5x-3x+3=-9

Step 3: Subtract 3 from both sides.
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6 0
3 years ago
Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621​
REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

a=-6

T_n=58

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here a_1=-6\ and\ a_2=-5

\therefore d=a_2-a_1=-5-(-6)=-5+6=1

Now we use the formula of A.P.

T_n=a+(n-1)d

On substituting the values, we get;

58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65

So there are 65 terms in between  -6 To 58.

That means we have to find the sum of 65 terms in between  -6 To 58.

Now we use the formula of Sum of n_terms.

S_n=\frac{n}{2}(2a-(n-1)d)

On substituting the values, we get;

S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

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3 years ago
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