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3 years ago

The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is th

Mathematics

1 answer:

Dafna11 [192]3 years ago

6 0

Answer:

$a + b \geq 30$

$b - a \geq 10$

Step-by-step explanation:

Given

The sum of the two positive integer a and b is at least 30, this means the sum of the two positive integer is 30 or greater than 30, so we write the inequalities as below.

$a + b \geq 30$

The difference of the two integers is at least 10, if b is the greater integer then we subtract integer a from integer b, so we write the inequality as below.

$b - a \geq 10$

Therefore, the following system of inequalities could represent the values of two positive integers a and b.

$a + b \geq 30$

$b - a \geq 10$

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If a+8 = 12 , then a =ayuda por favor

NARA [144]

Answer:

a = 4

Step-by-step explanation:

a+8 = 12

a= 12-8

a=4

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3 years ago

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Evaluate M^2 /p^2 for M = 10, N =-5p and P = -2

kondaur [170]

<u>Answer: </u>

The solution of $\bold{\frac{M^{2}}{P^{2}}}$ for M = 10, N = -5P and P = -2 is 25

<u>Solution: </u>

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of $\frac{M^{2}}{P^{2}}$ ,

By substituting the values of M and N, we get

$\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$

Expanding $\bold{10^{2}}$ :

Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.

$10^{2} = 10 \times 10 = 100$

Similarly expanding $\bold{(-2)^{2}}$ :

Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.

$(-2)^{2} = -2 \times -2 = 4$

So the equation $\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$ becomes,

$\frac{M^{2}}{P^{2}} = \frac{100}{4}$

By dividing 100 by 4 , we get the result as 25

Hence the solution of $\bold{\frac{M^{2}}{P^{2}}}$ when M = 10 and P = -2 is 25

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3 years ago

In the cube shown below, the distance between vertices 2 and 6 is 18 cm.

Aleks [24]

Answer:

Step-by-step explanation:

<h3>sana po makatulong</h3>

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3 years ago

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Can someone please help me !

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$2)~3x\to\text{Linear Monomial, because it's of 1st degree.}\to B\\\\
3)~2x^4-x+5\to\text{Quartic Trinomial, because it's of 4th degree.}\to C\\\\
4)~(2x^2-5x+6)+(5x^2-3x+4)=(2x^2+5x^2)-(5x+3x)+(6+4)\\\\
=7x^2-8x+10\to A$

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3 years ago

Whose stone hit the water first? (options lins stone, clares stone) When did that happen? (options 1/2 second after stone was to

slega [8]

Answer:

1) Clare's stone hit first.

2) 1 seconds.

3) Same maximum height for both.

4) 9 feet

Part A:

h = (-16t -8)(t - 1)

When the stone hits the water, the height will be 0

⇒ (-16t - 8)(t - 1) = 0

⇒ -16t - 8 = 0, t - 1 = 0

<u>simplify</u>

⇒ t = -1/2, t = 1

So, time was 1 seconds for Clare and 1.25 seconds or Lin. Clare's hit first.

Part B:

For Lin's stone: maximum height: 9 feet.

For Clare stone: (-16(0.25) - 8)((0.25) - 1) = 9 feet

No both stone reached the maximum height of 9 feet.

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2 years ago