Question

The following distribution shows the frequency of daily revenue for an Italian restaurant in Wilmington, Delaware. Revenue Frequency Under $2,000 18 $2,000 to under $4,000 10 $4,000 to under $6,000 26 $6,000 to under $8,000 14 $8,000 to under $10,000 8 Over $10,000 4 What is the probability that a randomly selected day will generate more than $6,000 in revenue

Answer 1

Answer:

The probability that a randomly selected day will generate more than $6,000 in revenue is 0.325.

Step-by-step explanation:

The frequency distribution of daily revenue for an Italian restaurant in Wilmington, Delaware is:

     Revenue      Frequency

   Under $2,000        18

$2,000 -  $4,000      10

$4,000 -  $6,000     26

$6,000 -  $8,000      14

$8,000 - $10,000       8

   Over $10,000           4

          Total                 80

The probability of an event E is defined as:

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcome

N = total outcomes

The favorable outcomes of the event X : "more than $6,000 in revenue" is defined as:

n (X) = 14 + 8 + 4 = 26

Total number of outcomes is, N = 80.

Compute the probability of the event X is:

$P(X)=\frac{n(X)}{N}=\frac{26}{80}=0.325$

Thus, the probability that a randomly selected day will generate more than $6,000 in revenue is 0.325.