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3 years ago

Find the zeros of the function F(x)=x^2-5x+5

1 answer:

6 0

You would have to replace f(x) with zero and use quadratic formula

f(x)=x^2-5x+5
0=x^2-5x+5

=(-b+-√b^2-4ac)/2a
=(5+-√25-4(1)(5))/2
=(5+-√5)/2

x=(5+√5)/2 or x=(5-√5)/2

Both x values are completely applicable in the equation.

Hope I helped :)

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Answer:

a) Figure attached

b) $P(234$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

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$P(234$

And we can find this probability with this difference:

$P(-2$

An we know using the graph in part a that this area correspond to 0.95 or 95%

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And we can find this probability with this difference:

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An we know using the graph in part a that this area correspond to 0.95 or 34+34+13.5+2.35%=83.85%

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And using the z score we got:

$P(X$

And that correspond to approximately 0.15%

Step-by-step explanation:

Part a

For this case we can see the figure attached.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part b

Let X the random variable that represent the length of human pregnancy of a population, and for this case we know that:

Where $\mu=266$ and $\sigma=16$

We are interested on this probability

$P(234$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(234$

And we can find this probability with this difference:

$P(-2$

An we know using the graph in part a that this area correspond to 0.95 or 95%

Part c

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And we can find this probability with this difference:

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An we know using the graph in part a that this area correspond to 0.95 or 34+34+13.5+2.35%=83.85%

Part d

We want this probability:

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And using the z score we got:

$P(X$

And that correspond to approximately 0.15%

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