The given plane, 
, has normal vector 
. Any plane parallel to this one has the same normal vector.
Let 
be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is
and this is perpendicular to 
.
So the equation of the plane is
or equivalently,
<span>solution of a system of linear equations</span>
Answer:
y = - 1/4 + 4
Step-by-step explanation:
y = 4x - 7
Slope = 4
Slope of the perpendicular line = -1/4
Point (8,2)
(b) y-intercept: 2 - (-1/4)(8)
= 2 + 2 = 4
11.6 because the square root of 135 is 11.61885.... and when you check it is approximately 135 because 11.6 *11.6 = 134.56, which can be rounded to 135
