Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:
×
7:14:21
Add 1,2,3 = 6
Divide 6 by 42=7
Then 7x1=7
7x2=14
7x3=21
Answer:
Use the slope-intercept form y=mx+b to find the slope m. m=−1
Step-by-step explanation:
lets take the x's away from: -5x+4x
That will be -5+4
-5+4=-1
Because remember:
When adding positive numbers, count to the right.
When adding negative numbers, count to the left.
When subtracting positive numbers, count to the left.
When subtracting negative numbers, count to the right.
I hope this helps. :)
