45 2/3 + 30 1/2 + 12 3/4=?

Can someone help me answer this?

andriy [413]

Answer:

m<S = 68 degrees.

m<D = 112 degrees

Step-by-step explanation:

Opposite angles of a parallelogram are equal so:

4x - 4 = 3x + 14

4x - 3x = 14 + 4

x = 18.

So m < S = 4(18) - 4

= 72-4

= 68 degrees.

Angles on the same side of a parallelogram are supplementary, so

m < D = 180 - 68

= 112 degrees.

7 0

2 years ago

JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the rhombus.

anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

$JL = 48$

$KM = 20$

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

$P = 2\sqrt{(JL)^2 + (KM)^2}$

Substitute values for JL and KM

$P = 2\sqrt{48^2 + 20^2}$

$P = 2\sqrt{2304 +400}$

$P = 2\sqrt{2704}$

$P = 2 * 52$

$P = 104$

Hence, the perimeter is 104 units

5 0

3 years ago

Jerald jumped from a bungee tower. If the equation that models his height, in feet, is h = –16t2 + 729, where t is the time in s

Snezhnost [94]

Answer. First option: t > 6.25

Solution:

Height (in feet): h=-16t^2+729

For which interval of time is h less than 104 feet above the ground?

h < 104

Replacing h for -16t^2+729

-16t^2+729 < 104

Solving for h: Subtracting 729 both sides of the inequality:

-16t^2+729-729 < 104-729

-16t^2 < -625

Multiplying the inequality by -1:

(-1)(-16t^2 < -625)

16t^2 > 625

Dividing both sides of the inequality by 16:

16t^2/16 > 625/16

t^2 > 39.0625

Replacing t^2 by [ Absolute value (t) ]^2:

[ Absolute value (t) ]^2 > 39.0625

Square root both sides of the inequality:

sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)

Absolute value (t) > 6.25

t < -6.25 or t > 6.25, but t can not be negative, then the solution is:

t > 6.25

5 0

3 years ago

Read 2 more answers

.Given the functions f(n) = 500 and g(n) = (nine tenths)n _ 1, combine them to create a geometric sequence, an, and solve for th

weeeeeb [17]

The original functions are: f(n) = 500 and g(n) = [9/10]^(n-1)

A geometric sequence combining them is: An = f(n)*g(n) = 500*[9/10]^(n-1):

Some terms are:
A1= 500
A2 = 500*[9/10]
A3 = 500*[9/10]^2
A4 = 500*[9/10]^3
....
A11 = 500*[9/10]^10 ≈ 174.339

Answer: the third option, An = 500[9/10]^(n-1); A11 = 174.339

4 0

3 years ago

Read 2 more answers

P;EASE HELP!!!!! Consider the leading term of the polynomial function. What is the end behavior of the graph? Describe the end

Marrrta [24]

The end behavior of a polynomial function is the behavior of the graph of f as
x → +∞ or x → -∞ , depending on its leading coefficient.

In the example, the LEADING COEFFICIENT = - 3x⁵
,when x → +∞, ( - 3x⁵ ) → - ∞ . The end behavior, the polynomial approches minus infinity

7 0

4 years ago

45 2/3 + 30 1/2 + 12 3/4=?​

45 2/3 + 30 1/2 + 12 3/4=?