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4 years ago

Decomposers such as fungi break down the nutrients in dead plant and animal matter for use by _______.

Advanced Placement (AP)

2 answers:

Pepsi [2]4 years ago

6 0

Producers use the dead plant and animal matter to remake organic compound.

svp [43]4 years ago

5 0

Fertilizer, or good soil

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PLEASE TRY FOR APWH IF UR LIKE ACC SMART WILL MARK BRAINLIEST FOR THOSE WHO KNOW AND GOT IT GRADED

Xelga [282]

WILL BRAINLIEST! psychology...
a description of the three topics, concepts, or theories you learned about in the module that you consider most important; choose topics, concepts or theories from at least three lessons in the module
an explanation of how what you have learned about these three topics, concepts, or theories can be applied in your own life or in the lives of others close to you
at least one paragraph for each topic, concept, or theory, for a total of at least three paragraphs; use this organizer to help you format your work

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3 years ago

1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a NET DECREASE of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.

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2 years ago

Trade on the Inca roads differed most strongly from trade on the Silk Road in which of the following ways?

Naily [24]

Answer:

I believe the correct answer is B: the Inca roads crossed mountains, while the Silk Road traveled through lowlands.

Explanation:

Since the Inca roads were in the mountains and I the silk road was on low lands. It would make sense for it to be B. But I could be mistaken.

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3 years ago

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Sphinxa [80]

Answer:

A. (As it is now)

Explanation:

Correct

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