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balandron [24]
3 years ago
9

A number lock has 9 different digits. a combination of three digits can be set to open the lock. how many combinations are possi

ble?
Mathematics
1 answer:
katrin2010 [14]3 years ago
6 0
There are 7 combinations sis
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two trains leave the station at the same time one heading west and the other East the westbound train travels at 55 miles per ho
Diano4ka-milaya [45]
Recall your d = rt, distance = rate * time

so... one train goes west and the goes the opposite way... alrite... so... notice, by the time 338 miles have been covered by both, it will have been "t" hours, and whatever "t" is, is the same amount of time the westbound train has been running as well as the eastbound train has been running.

now, let's say, since by "t" hours they've covered 338 altogether, so, if the westbound train has covered say "d" miles, then the eastbound train would have covered the slack from 338 and d, that is, "338 - d".

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
Westbound&d&55&t\\
Eastbound&338-d&75&t
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=55t\\
338-d=75t\\
----------\\
338-\boxed{55t}=75t
\end{cases}
\\\\\\
338=75t+55t\implies 338=130t\implies \cfrac{338}{130}=t\implies \stackrel{hours}{2.6}=t

so, 2hours and 36 minutes.
8 0
3 years ago
Find angle abc i really need help this is for geometry
Ghella [55]
The answer is 83 ....

5 0
3 years ago
Solve for the indicated variable.
marta [7]

Answer:

Option (c) "r=\dfrac{q}{4c}-h"

Step-by-step explanation:

The given equation is :

q = c4(h + r)

We need to solve it for r.

Dividing both sides of the given equation by 4c.

\dfrac{q}{4c}=\dfrac{4c}{4c}(h+r)\\\\(h+r)=\dfrac{q}{4c}

Now, subtract h both sides of the equation.

h+r-h=\dfrac{q}{4c}-h\\\\r=\dfrac{q}{4c}-h

Hence, this is the required solution.

3 0
2 years ago
A rental car agency charges a flat fee of $139.00 plus $30.00 per day to rent a certain car. Another agency charges a fee of $13
Sveta_85 [38]
139 + 30d = 13 + 51d
139 - 13 = 51d - 30d
126 = 21d
126/21 = d
6 = d

now lets check..
139 + 30d = 139 + 30(6) = 319
13 + 51d = 13 + 51(6) = 319

so on day 6, they will both cost $ 319

5 0
3 years ago
Factor completely: 3a2 − 14a − 24
GalinKa [24]
I know what it is. it  is (3a+4)(a-6)
7 0
3 years ago
Read 2 more answers
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